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A rectangle has perimiter 84 ft you also know that the length of the rectangle is six times of the width find the area of this rectangle?
Wiki User
∙ 14y ago
L + W = P/2 = 42 ft. 1/7th of 42 is 6 so L = 36 and W = 6 making the area 216 sqft.
Wiki User
∙ 14y ago
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What is perimiter for a rectangle?
Twice (length + width)
What is length times width equal?
length times width equals the area of a rectangle. length times width equals the area of a rectangle. area
What is the length of a rectangle if the perimiter is 100 feet and the width is 20 feet?
The perimeter of a rectangle is twice the length plus twice the width.20' x 2 = 40'100' - 40' = 60'60' / 2 = 30'
Do you times area of a rectangle?
The area of a rectangle is found by multiplying the length times the width.
When the perimiter of the rectangle is 38 inches If the rectangle is less than 4 times the width find the area of the rectangle Confused how to do this?
I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.
What is perimiter for a rectangle?
Twice (length + width)
The length of a rectangle is twice its width If the perimeter of the rectangle is 30yd find its area?
length=2x width=x perimiter=2x+2x+x+x=30= 6x=30 divide by 6, x=5 area=length times width= 2(5)times 5 = 10 times 5= 50yd
What of a rectangle is the product of the length and width?
It is the area of the rectangle which is length times width
What is length times width equal?
length times width equals the area of a rectangle. length times width equals the area of a rectangle. area
What is the length of a rectangle if the perimiter is 100 feet and the width is 20 feet?
The perimeter of a rectangle is twice the length plus twice the width.20' x 2 = 40'100' - 40' = 60'60' / 2 = 30'
Formula for finding the area of a rectangle?
A = lw Area of a rectangle = length times width
What is the width of a rectangle is 11 feet its length is three times longer than it width What is the area of the rectangle?
Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet
Area of rectangle-?
length times width
How do you work out perimiter?
In a regular quadrilateral, it's two times the sum of the length and width.
Do you times area of a rectangle?
The area of a rectangle is found by multiplying the length times the width.
When the perimiter of the rectangle is 38 inches If the rectangle is less than 4 times the width find the area of the rectangle Confused how to do this?
I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.
How do you find length in the area of rectangle and its width?
multiply length times height times width
