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Acceleration = (change in speed) divided by (time for the change).
From the figures given in the question, the acceleration is ( 49/3 ) = 16.33 m/sec2 .
There's no way that this is happening on the moon. That acceleration is about 67% greater
than the acceleration of gravity on the earth's surface. It should be about 83% less, or about 1.63 m/sec2.
I see the problem now. The '49' in the question should be '4.9'.
apex- 1.63 m/s2
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A rock dropped on the moon will increase its speed from 0 ms its starting speed when first dropped to 4.9 ms in about 3 seconds What value do you calculate for the magnitude of the acceleration o?
1.63 m/s2
How do you calculate acceleration from velocity?
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
Calculate percentage increase from 18 to 23 percent?
There is a 5% increase. (23 - 18)If you meant the percentage increase from 18 to 23. It is a 27.77% increase.percentage increase = ( a - b ) / aa = larger ending numberb = smaller starting number
What is the percent increase from 10 to 25?
to calculate the percent increase . first = 25 - 10 = difference between the two numbers = 15 then divide this differnece by the original starting number (which is 10)= 15 divided by 10 = 1.5 to make this a percent increase multiply by 100 . so you result is 1.5 x 100 = 150% to summarise: ((final number- starting number) / starting number) x 100 = percent increase
The vector has a magnitude of 11 and a direction of 20 degrees. What is the magnitude of the x component?
Assuming the 20 degrees are measured counterclockwise, starting from the x-axis (this is more or less standard), you can calculate the x-component as 11 x sin(20). Make sure your calculator is set to degrees first.
