Wiki User
∙ 11y agoAfter 3.5 seconds of free-fall on or near the surface of the Earth, (ignoring effects
of air resistance), the vertical speed of an object starting from rest is
g T = 3.5 g = 3.5 x 9.8 = 34.3 meters per second.
With no initial horizontal component, the direction of such an object's velocity
when it hits the ground is straight down.
Wiki User
∙ 11y agoIf the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
Let v be the velocity when the ball is at 640 feets going downwards v = 48 feet /sec let the velocity with which it reaches the ground be u then, u2=v2+2gh g = acc due t ogravity in feet/sq.sec h = 640 feet the time taken to reach the ground = time to return to 640ft + the time to fall from there Time taken to get to the ground is 8 seconds. Final velocity is 208 feet per second downwards
In two seconds of fall, the speed increases 19.6 meters (64.4 feet) per second. The magnitude of velocity increases by that amount, while the direction of velocity doesn't change.
A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
Acceleration = (change in velocity) / (time for the change)9.8 = (change in velocity) / (2 seconds)9.8 x 2 = change in velocity = 19.6 meters per second .Hint: The mass of the object and the height of the building are there just tothrow you off balance. You don't need either of them to answer the question.
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.
To calculate the velocity of the ball, we need to know the height from which it was dropped. If the ball was dropped from rest, we can use the formula for free fall motion: velocity = (acceleration due to gravity * time). Assuming the acceleration due to gravity is 9.81 m/s^2, the velocity of the ball hitting the ground after 3.03 seconds would be around 29.7 m/s.
The velocity of an object will increase as it falls towards the ground due to the acceleration of gravity. However, once it reaches terminal velocity, its velocity will remain constant.
If the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
The speed of the ball when it reaches the ground can be calculated using the kinematic equation: v = u + gt, where v is the final velocity (speed), u is the initial velocity (0 m/s as it's dropped), g is acceleration due to gravity (9.8 m/s^2), and t is the time taken (5.5 s in this case). Plugging in the values, v = 0 + 9.8 * 5.5 = 53.9 m/s. So, the speed of the ball when it reaches the ground would be approximately 53.9 m/s.
The acceleration of the ball can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the initial velocity is 0 m/s, the final velocity is 20 m/s, and the time is 2 seconds. Therefore, the acceleration would be (20 m/s - 0 m/s) / 2 s = 10 m/s^2.
When a ball is dropped, it starts with an initial velocity of zero. However, as it falls towards the ground, it accelerates due to gravity, causing its velocity to increase. Therefore, the velocity of the ball is non-zero as it falls towards the ground.
The thrown ball will have a greater speed when it reaches ground level because it has a horizontal component of velocity in addition to the vertical component. The rock only has a vertical component of velocity due to gravity.
The rock will have a greater speed when it reaches the ground level compared to the ball thrown horizontally because the rock will be accelerated by gravity as it falls vertically, while the ball thrown horizontally will only have its initial horizontal velocity.
The velocity of the tomato when it hits the ground will be determined by its initial velocity, the force of gravity acting upon it, and any air resistance. It will likely be accelerating towards the ground due to gravity until it reaches its terminal velocity upon impact.
is constantly decreasing until it reaches zero when she reaches terminal velocity. At that point, her acceleration is zero and she falls at a constant speed, experiencing air resistance equal in magnitude to her weight.
Let v be the velocity when the ball is at 640 feets going downwards v = 48 feet /sec let the velocity with which it reaches the ground be u then, u2=v2+2gh g = acc due t ogravity in feet/sq.sec h = 640 feet the time taken to reach the ground = time to return to 640ft + the time to fall from there Time taken to get to the ground is 8 seconds. Final velocity is 208 feet per second downwards