Ignoring air resistance, any falling object falls 4.23 feet in the first 0.513 second.The horizontal distance doesn't matter, and we don't need to know it. The time it takes to hitthe floor after it rolls off the edge has nothing to do with how fast it was rolling before it fell.
19.6m
3 strikes
Strikes has one syllable.
When light strikes a rough surface it reflects in essentially random directions.
The time the ball was in the air can be calculated using the horizontal distance it traveled and its initial horizontal velocity. Time = distance / velocity. In this case, time = 45m / 15 m/s = 3 seconds.
Strikes and dips are associated with the orientation of rock layers. The strike is the compass direction of a horizontal line on the rock surface, while the dip is the angle of inclination of the rock layer from the horizontal plane. They are fundamental in understanding the structural geology of rock formations.
Well, let's think about this together. The horizontal distance the ball travels is 45 meters, and we know the initial horizontal velocity is 15 m/s. Using the formula for horizontal distance, time, and velocity, we can calculate the time it takes for the ball to reach the ground. Then, we can use this time in the vertical motion formula to find the height of the cliff. Remember, mistakes are just happy accidents in the world of math!
Ignoring air resistance, any falling object falls 4.23 feet in the first 0.513 second.The horizontal distance doesn't matter, and we don't need to know it. The time it takes to hitthe floor after it rolls off the edge has nothing to do with how fast it was rolling before it fell.
For the projectile to land at the same distance with the same initial speed, it must be launched at an angle of 15 degrees from the horizontal. This is because the range of a projectile is maximized when launched at a 45-degree angle. So, launching at 15 degrees in the opposite direction of 75 degrees should bring the projectile to the same landing point.
Well by using the equation Speed = Distance / Time.So, if the speed is 1.35 m/s and the time is 0.4s, then 1.35 = distance / 0.4by rearranging the equation we get, 1.35 x 0.4 = distance.therefore the distance travelled is 0.54 metres = 54 cm.
The time it takes to hear thunder after lightning strikes is typically about 5 seconds for every mile of distance between you and the lightning.
19.6m
so that when the lightning strikes it makes the lightning not burn the tower.
To solve this problem you use the derived formula ∆dh=(V1h2(sin2Ѳ))/g 250m=V1h2(sin2(17))/9.8m/s2 V1h=((sin(17))/9.8m/s2)1/2 V1h= 64.7292201m/s V1h= 65m/s
To solve this problem you use the derived formula ∆dh=(V1h2(sin2Ѳ))/g 250m=V1h2(sin2(17))/9.8m/s2 V1h=((sin(17))/9.8m/s2)1/2 V1h= 64.7292201m/s V1h= 65m/s
could never get a full week in because of strikes