Assuming it is spherical: area = 4 x pi x radius2. Replace the area, and solve.
The volume of a balloon is like that of a sphere. So we use 4/3x Pix radius3 .Now plug in some numbers for V and see how radius changes. You will see if you go from a small volume to one a little larger, say .1 to .15, there is a pretty big change in the radius. Now try 1000 to 1000.15. You will see the change in the radius is much smaller.That is because of the fact the radius is cubed. I can't draw it here, but have a look at the graph of x cubed and that may shed some light on it.
volume of spherical = 4/3*Pi*Radius^3 = 4/3*3.14*32^3=137188
It is the distance from the centre to all points on the surface of a sphere with a radius of 1 foot.
Radius(air) = 3
To calculate the new volume of a balloon after it has been inflated, you can use the formula for the volume of a sphere, which is V 4/3 r3, where V is the volume and r is the radius of the balloon. Measure the radius of the inflated balloon and plug it into the formula to find the new volume.
To find the volume of an inflated balloon, you can measure its diameter using a ruler and then use the formula for the volume of a sphere, V = (4/3) * pi * r^3, where r is the radius (half of the diameter) of the balloon. Plug in the radius and calculate the volume. Alternatively, you can submerge the inflated balloon in a container of water and measure the water displacement to find the volume of the balloon.
If the surface area of a spherical balloon increases by 11%, the radius will increase by approximately 3.3%. This relationship is based on the formula that relates surface area to radius in a sphere (Surface Area = 4πr^2).
Assuming the balloon is perfectly spherical and that the 12" you state refers to the diameter of the balloon then it is obviously 6". If you can't assume any of the above then your question cannot be answered.
Its radius of curvature and its reflecting property
Assuming it is spherical (since it has a specific radius) then Volume = (4/3)pi*radius^3, so V = (4/3)pi*7^3 = 1436.76 cu. in.
The change in the area would increase by a factor of 4. When the diameter doubles, the radius also doubles. Since the formula for the surface area of a sphere is 4πr^2, when the radius doubles, the area increases by a factor of 4.
Assuming it is spherical: area = 4 x pi x radius2. Replace the area, and solve.
this is funny cause i took an online test with this question
The volume of a balloon is like that of a sphere. So we use 4/3x Pix radius3 .Now plug in some numbers for V and see how radius changes. You will see if you go from a small volume to one a little larger, say .1 to .15, there is a pretty big change in the radius. Now try 1000 to 1000.15. You will see the change in the radius is much smaller.That is because of the fact the radius is cubed. I can't draw it here, but have a look at the graph of x cubed and that may shed some light on it.
You mean the surface area, right? Assuming the balloon is approximately spherical, you can measure the diameter, divide by two to get the radius & plug that into this formula.A=¾πr²Where A is the area, r is the radius and π is the ratio of the circumpherence to the radius of a circle. 3.14 or 22/7 are good approximations to π, also a decent calculator will have a better approximation built in. To look it up search for "pi" (that's the Greek letter's name).
volume of spherical = 4/3*Pi*Radius^3 = 4/3*3.14*32^3=137188