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A spherical balloon is inflated at a rate of 10 cm cube per sec what is the change in its radius when it's radius is 10 cm?
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How do you calculate the radius of a balloon with an area of 1200 meters squared?
Assuming it is spherical: area = 4 x pi x radius2. Replace the area, and solve.
Why does the rate of change of the radius of a balloon slow down as the balloon gets bigger?
The volume of a balloon is like that of a sphere. So we use 4/3x Pix radius3 .Now plug in some numbers for V and see how radius changes. You will see if you go from a small volume to one a little larger, say .1 to .15, there is a pretty big change in the radius. Now try 1000 to 1000.15. You will see the change in the radius is much smaller.That is because of the fact the radius is cubed. I can't draw it here, but have a look at the graph of x cubed and that may shed some light on it.
What is the radius of a 32 foot spherical water tank?
volume of spherical = 4/3*Pi*Radius^3 = 4/3*3.14*32^3=137188
What is the spherical radius of 1 foot?
It is the distance from the centre to all points on the surface of a sphere with a radius of 1 foot.
The radius of a balloon which depends on the amount of air inside is 3 inches?
Radius(air) = 3
