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β 11y ago2.75 * 10^-7 t
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β 11y agoHow deep is the box? (Need to know the volume of the box). It is 2.25 cu in per 12AWG conductor, and it does not matter if it carries current or not.
The magnitude of a vector is a geometrical value for hypotenuse.. The magnitude is found by taking the square root of the i and j components.
It is the positive square root of its length.
Go 140 units of distance in any direction. Turn 90 degrees clockwise and go 140 units of distance in a straight line. Turn 90 degrees clockwise and go 140 units of distance in a straight line. Turn 90 degrees clockwise and go 140 units of distance in a straight line.You will have travelled along a square route whose total distance is 560 units. Alternatively you could have turned counter clockwise each time.
Go 11 units of distance in any direction. Turn 90 degrees clockwise and go 11 units of distance in a straight line. Turn 90 degrees clockwise and go 11 units of distance in a straight line. Turn 90 degrees clockwise and go 11 units of distance in a straight line.You will have travelled along a square route whose total distance is 44 units. Alternatively you could have turned counter clockwise each time.
To find the magnitude of the resultant vector, you can use the Pythagorean theorem. Simply square the x-component, square the y-component, add them together, and then take the square root of the sum. This will give you the magnitude of the resultant vector.
How deep is the box? (Need to know the volume of the box). It is 2.25 cu in per 12AWG conductor, and it does not matter if it carries current or not.
The magnitude of a vector is a geometrical value for hypotenuse.. The magnitude is found by taking the square root of the i and j components.
Conductor area refers to the cross-sectional area of a conductor, such as a wire or cable, that carries an electric current. It is typically measured in square millimeters or square inches and is an important factor in determining the current-carrying capacity and resistance of the conductor. A larger conductor area generally allows for more current to flow with lower resistance.
It is the positive square root of its length.
The magnitude of a vector F(x,y) is given by the square root of (x^2 + y^2). So for F = 30i - 40j, the magnitude would be the square root of (30^2 + (-40)^2), which equals approximately 50.0.
Go 1.75 units of distance in any direction. Turn 90 degrees clockwise and go 1.75 units of distance in a straight line. Turn 90 degrees clockwise and go 1.75 units of distance in a straight line. Turn 90 degrees clockwise and go 1.75 units of distance in a straight line.You will have travelled along a square route whose total distance is 7 units. Alternatively you could have turned counter clockwise each time.
Go 144 units of distance in any direction.Turn 90 degrees clockwise and go 144 units of distance in a straight line.Turn 90 degrees clockwise and go 144 units of distance in a straight line.Turn 90 degrees clockwise and go 144 units of distance in a straight line.You will have travelled along a square route whose total distance is 576 units.Alternatively you could have turned counter clockwise each time.
Go 1.75 units of distance in any direction. Turn 90 degrees clockwise and go 1.75 units of distance in a straight line. Turn 90 degrees clockwise and go 1.75 units of distance in a straight line. Turn 90 degrees clockwise and go 1.75 units of distance in a straight line.You will have travelled along a square route whose total distance is 7 units. Alternatively you could have turned counter clockwise each time.
Go 52 units of distance in any direction. Turn 90 degrees clockwise and go 52 units of distance in a straight line. Turn 90 degrees clockwise and go 52 units of distance in a straight line. Turn 90 degrees clockwise and go 52 units of distance in a straight line.You will have travelled along a square route whose total distance is 208 units. Alternatively you could have turned counter clockwise each time.
Go 250000000000 units of distance in any direction. Turn 90 degrees clockwise and go 250000000000 units of distance in a straight line. Turn 90 degrees clockwise and go 250000000000 units of distance in a straight line. Turn 90 degrees clockwise and go 250000000000 units of distance in a straight line.You will have travelled along a square route whose total distance is 1000000000000 units. Alternatively you could have turned counter clockwise each time.
Go 11.5 units of distance in any direction. Turn 90 degrees clockwise and go 11.5 units of distance in a straight line. Turn 90 degrees clockwise and go 11.5 units of distance in a straight line. Turn 90 degrees clockwise and go 11.5 units of distance in a straight line.You will have travelled along a square route whose total distance is 22 units. Alternatively you could have turned counter clockwise each time.