At the end of 3 seconds, a falling object is falling at 65.8 mph faster than when it was released, ignoring air resistance.
D. 36 m/s
Surface area is ONE thing that can affect how fast an object falls. Two forces determine how fast an object falls - the force of gravity and the opposing drag on the object from the medium it is falling through. In the case of an object falling in a vacuum, there is no drag so the object falls strictly according to the law of gravity. If an object is dropped through a fluid such as air or water, it can reach a terminal velocity where the force of gravity is exactly counterbalanced by the opposing drag on the object. In this case acceleration ceases - although motion does not. In other words, the object continues to fall, but it doesn't speed up. Drag force is a function of object velocity, viscosity of the fluid it is falling through, the surface area of the falling object, the surface roughness of the falling object, and the geometry of the falling object (spheres usually have less drag than cubes for example).
Acceleration due to gravity is approx 9.8 metres/second2 So after 2.3 seconds, the velocity of the rock is 9.8*2.3 = 22.54 metres/second
10
92.2m/s
They do fall. But they're traveling fast enough so that the surface of the Earth falls away from them as fast as they are falling. Same thing that keeps the Earth from falling into the sun.
At the end of 3 seconds, a falling object is falling at 65.8 mph faster than when it was released, ignoring air resistance.
D. 36 m/s
A 92.2 m/s V = (4 m/s) + (9.8 m/s²) (9 s) V = 92.2 m/s
Surface area is ONE thing that can affect how fast an object falls. Two forces determine how fast an object falls - the force of gravity and the opposing drag on the object from the medium it is falling through. In the case of an object falling in a vacuum, there is no drag so the object falls strictly according to the law of gravity. If an object is dropped through a fluid such as air or water, it can reach a terminal velocity where the force of gravity is exactly counterbalanced by the opposing drag on the object. In this case acceleration ceases - although motion does not. In other words, the object continues to fall, but it doesn't speed up. Drag force is a function of object velocity, viscosity of the fluid it is falling through, the surface area of the falling object, the surface roughness of the falling object, and the geometry of the falling object (spheres usually have less drag than cubes for example).
Acceleration due to gravity is approx 9.8 metres/second2 So after 2.3 seconds, the velocity of the rock is 9.8*2.3 = 22.54 metres/second
The object will be falling at 49 m/s.This is solved by multiplying the force of gravity (9.8 m/s) by the time you're calculating (5s).
Assuming the acceleration due to gravity is 9.8 m/sĀ², the apple would be falling at 9.8 m/s when it hits the ground after 1 second.
As is typical of this type of question, I am going to assume that the falling bowling ball is not affected by the friction of the air through which it falls. The formula for velocity is v = gt where g is acceleration due to gravity, 9.8m/sec2 After 8 seconds, the ball is falling at v = 9.8m/sec2 * 8 sec = 78.4 m/sec. If it really has a mass of 10kg, it's not a bowling ball. Bowling balls are limited to about 7.27 kg.
very fast how fast can u fall
0,02637 seconds -> Fast.