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Why is a number raise to zero is equal to one?
x to the n divided by x to the n is 1. By the law of powers x to the power n divided by x to the power n is x to the power (n minus n), ie x to the power zero. Things which are equal to the same thing are equal to each other. Therefore x to the power zero = 1. (Unless x = zero!)
What is 2n to the second power divided by n?
2n2 / n = 2n
What is 2 to zero power?
1. All numbers to the zero power are 1. Take any number a^n we know that a^n/a^n=1 since anything divided by itself is 1. We also know the rule for division tells us a^n/a^n= a^(n-n)=a^0. so it is 1. 0^0 is usually defined as 1, but in some context people say it is indeterminate.
Why is anything to the power of one?
It isn't. You're thinking of anything to the power zero. x0 = x(n - n) which equals xn divided by xn which equals 1.
What is n raised to the power n-1?
n-1 = 1/n
Why is a number raise to zero is equal to one?
x to the n divided by x to the n is 1. By the law of powers x to the power n divided by x to the power n is x to the power (n minus n), ie x to the power zero. Things which are equal to the same thing are equal to each other. Therefore x to the power zero = 1. (Unless x = zero!)
How any number o the power of zero is one?
The law of powers requires that xn divided by xm = x(n - m). Consider this when n = m: xn divided by xn = x(n - n), ie 1 = x0. x2 = x times x x1 = x times x divided by x ie x x0 = x divided by x = 1 x-1 = 1 divided by x = 1/x x-2 = 1/x divided by x ie 1/x2 etc
Why is 6 to the power 0 equal to 1?
Anything to the power 0 is 1. Using the laws of powers to get to x to the power n-1 from x to the power n you divide by n; eg to get 4 squared (16) from 4 cubed (64) you divide 64 by 4. If you start with x to the power 1 and want x to the power zero, you divide by x. And x divided by x is 1.
What is power to zero?
1. All numbers to the zero power are 1. Take any number a^n we know that a^n/a^n=1 since anything divided by itself is 1. We also know the rule for division tells us a^n/a^n= a^(n-n)=a^0. so it is 1. 0^0 is usually defined as 1, but in some context people say it is indeterminate.
What is 2n to the second power divided by n?
2n2 / n = 2n
Why is anything to the power of one?
It isn't. You're thinking of anything to the power zero. x0 = x(n - n) which equals xn divided by xn which equals 1.
Why does any number to the zero power equal one?
Here is why any number to the zero power equals one. Consider this. a^b. it is natural to restrict a > 0, but we'll only assume that number b is any real number. We'll use the natural exponential function defined by the derivative of the exponential function. Now we have a^r=e^rln(a). And we know that e^rln(a)=e^((ln(a))^r), where a >0 and r is in the domain of all real numbers negative infinity to infinity. We can apply this definition to any number a to any power r. Particularly, a^0. By the provided definition, a^0=e^(0*ln(a))=e^0=1. Furthermore, a^1=e^(1*ln(a))=e(ln(a))=a. And a^2=(e^(ln(a))^2)=a^2. ---------------------------------- Here is a simpler approach: In general, a^n/a^m = a^(n-m) and a/a = 1. We can use these facts to prove that x^0 = 1 so long as x isn't 0. First, state the obvious: 1 = 1 Next, since any non-zero number divided by itself is one: 1 = a^n/a^n (It doesn't change how the equation looks, but for the sake of being thorough, you could subsitute (a^n/a^n) in place of 1 in the original equation.) Then, since dividing like bases requires that you subtract their exponents: a^n/a^n = a^(n-n) = a^0 Substitute (a^0) in for (a^n/a^n) and you obtain: a^0 = 1 There are two reasons "a" cannot be 0 in this proof: firstly, raising 0 to non-zero powers would still result in zero, so "a" being 0 would cause division by zero in the initial theorems we used, and secondly, 0^0 is considered undefined in itself.
What are two phrases you can write for 150 divided by n?
1) One hundred and fifty divided by n; 2) n divided into one hundred and fifty.
What is the integral of x to the power n?
For n not equal to -1, it is 1/(n+1)*xn+1 while for n = -1, it is ln(|x|), the logarithm to base e.
If N is a nonzero integer then n plus 1 divided by n is always greater than 1?
2
What is the sum of 20 divided by a number and that number divided by 20?
1
What is the answer to 4 divided by 8 over n to the power of 3?
(4/8)/(n^3)...4/8 reduces to 1/2 so the problem reduces to (1/2)/(n^3)...Which written in simple terms is 1/n^3. Actually I made a typo the answer is 1/(2n^3) Sorry about that.
