2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
2n-3 = 9 solve for n by first adding 3 to both sides 2n = 12 divided both sides by 2 n = 6
3n+3=n+7 3n+3-n=n+7-n (subtract n from both sides) 2n+3=7 2n+3-3=7-3 (subtract 3 from both sides ) 2n=4 2n/2=4/2 (divided by 2 on both the sides) n=2 Answer: n=2
n/27=2n/27*27=2*27n=54
n * 2n = 2n2
34 divide by 4n 34 - 4n cause 2nx2 is 2n+2n 2n is n+n so it is n+n+n+n =4n
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
2
2n-3 = 9 solve for n by first adding 3 to both sides 2n = 12 divided both sides by 2 n = 6
2n This is all that can be said since you didn't identify the power n.
Meiosis produces haploid gametes which have the ' n ' symbol.
3n+3=n+7 3n+3-n=n+7-n (subtract n from both sides) 2n+3=7 2n+3-3=7-3 (subtract 3 from both sides ) 2n=4 2n/2=4/2 (divided by 2 on both the sides) n=2 Answer: n=2
n/27=2n/27*27=2*27n=54
n * 2n = 2n2
The cardinality (size) of the power set of a set with n elements is 2n.
Let the number be 'n', then the calculation becomes :- 5/n - 3 = 7/2n . . . multiply throughout by 2n 10 - 6n = 7 6n = 3 n = 1/2
n equals p over 2(like as a division problem. See, you just write n+2n=p then you do this- n+2n=p you take 2 divided by 2 and those cancel ou so if you divide by one so=ide, you have to do it to the other. so you get your answer.