120 km/hr (1000 meters/1 km)(1 hr/60 minutes)
= 2000 meters per minute
---------------------------------
33.33 meters per second.
18 kilometers per hour.
30,000 metres or 30km
The passanger train had traveled 216000 meters by the end of this minute
1800 meters
Average acceleration over an interval of time = (final speed - initial speed) / (time for the change)= [ (0 - 30) / 1 ] (meters / second-minute) = [ (0 - 30) / (60) ] (meters / second-second) =-0.5 meter / sec2
If a train that goes 500 meters every 10 seconds you will cover 30,000 meters in 10 minutes. <><><> There are 6 units of 10 seconds to a minute. 6x500= 3000 meters per minute. X 10 minutes= 30,000
120 Kilometres = 120,000 metres There are 60 minutes in an hour 120,000 divided by 60 = 2,000 2,000 metres per minute (or 2 Kilometres per minute)
33.33 meters per second.
The average speed of the train is 41 meters per second. This is calculated by dividing the distance traveled by the time taken: 861 meters / 21 seconds = 41 meters per second.
18 kilometers per hour.
The train travels 150m in 10seconds, Therefore it travels 900m in 1 minute and thus 54000 metres in 1 hour. The train's speed is therefore 54 kph (kilometres per hour)
800 meters
454 km
120 km/hr *1000 m/km * 1 hour/60 minutes * 1 minute/60 seconds = 33.333... m/sec
33,055m or 33.055Km
30,000 metres or 30km