120 km/hr *1000 m/km * 1 hour/60 minutes * 1 minute/60 seconds = 33.333... m/sec
The train travels 150m in 10seconds, Therefore it travels 900m in 1 minute and thus 54000 metres in 1 hour. The train's speed is therefore 54 kph (kilometres per hour)
20 feet in 0,5 seconds ==> 40 feet per second 40 feet per second * 3 seconds = 120 feet
The train travels at 123.7 km/h
For this you have to work out the speed speed=distance/time therefore the speed here is 20feet/15seconds = 1.3333333m/s Now you have to work out the distance distance = speed X time the distance traveled in 3 seconds is 1.3333333m/s x 3 = 4 feet
18 miles
The average speed of the train is 41 meters per second. This is calculated by dividing the distance traveled by the time taken: 861 meters / 21 seconds = 41 meters per second.
33,055m or 33.055Km
30,000 metres or 30km
If a train that goes 500 meters every 10 seconds you will cover 30,000 meters in 10 minutes. <><><> There are 6 units of 10 seconds to a minute. 6x500= 3000 meters per minute. X 10 minutes= 30,000
33.33 meters per second.
The train travels 150m in 10seconds, Therefore it travels 900m in 1 minute and thus 54000 metres in 1 hour. The train's speed is therefore 54 kph (kilometres per hour)
454 km
After the nose of the train reaches the platform, it takes some number of seconds for thenose to reach the far end. At that time, the whole train is lined up with the whole platform.Then after that, it takes the same number of seconds again for the caboose to reach the far end,and the train to completely clear the platform.So the total time that there's some overlap between the train and platform is twice the timethe train takes to move the length of the platform, which is also the length of the train.Distance = (speed) x (time)180 meters = (speed) x (9 seconds)speed = (180/9) = 20 meters per second
200m. Here's the work:The speed of the train in meters per second is:(36km/hr)(1000m/km) / (3600s/hr) = 10 m/sIf it takes 80 seconds to cross, then the distance traveled in 80s at 10m/s is:(10m/s)(80s) = 800mNow, imagine this:The front end of the train travels 800 meters from the time it reaches the bridge until the back end is clear of the bridge. This means that the length of the train equals the distance traveled minus the length of the bridge.So:800m - 600m = 200mThe train is 200m long.
Completely ignore the first train.The second train passes the pole in 8sec.In this 8 seconds the train drove 120 meters.So the train has a speed of 15meters per second (120/8=15).Answer: 15 (meters / second) = 54 km/h
A normal train usually travels at a speed of 100mph.
120 km/hr (1000 meters/1 km)(1 hr/60 minutes) = 2000 meters per minute ---------------------------------