Wiki User
∙ 12y agoWhen i will be a pro will help
Wiki User
∙ 12y agoNot really. Neglecting air resistance just makes it easier to solve equations and grasp concepts. If one were to actually be collecting data from your experiment, they would have to take in air resistance, especially if the object's cross section were high and/or density was low.
if length is doubled then resistivity increases&when area is doubled resistivity decreases.
There are several different "oval" shapes. A running track, which comprises two semicircles separated by two straight stretches is an oval. So is the cross section of an egg - a shape in which the cross-sectional width does not change uniformly. Another example is the ellipse. Because all these shapes are called ovals, there is no single name.
1 section = 640 acres. A quarter section = 160 acres.
The answer depends on what the section is of.
A piece of wire stretched such that its length increases and its radius decreases will tend to have its resistance increase. The formula for this is: R = ρL/A where ρ = resistivity of the material composing the wire, L = length of the wire, and A = area of the conducting cross section of the wire. It can easily be seen that as area decreases resistance gets higher. In the case proposed the wire length is not reduced as it is stretched to reduce the area, this increases the resistivity as well.
The resistance of a material is defined as: R = r * l / A where r (actually it is the Greek alphabet rho) is the specific resistance and is independent of shape, structure, etc, but is specific to the material only; l is the length and A is the area of cross section. Let R1 = r * (l1/A1) and after stretching it becomes R2 = r * (l2/A2) R2/R1 = (l2/l1)*(A1/A2) -------------------------- equation 1 If the wire has been stretched with no loss of material, the volume remains the same. Hence, l1A1 = l2A2 which gives A1 = A2*(l2/l1). given that (l2/l1) is 1.25, we get A1/A2 = 1.25 Using this value in equation 1, we get R2/R1 = 1.25 * 1.25 = 1.5625 Hence, the resistance of the wire increases by a factor of 1.5625. - Karthik
A wire with a larger cross section has lower resistance because there is more space for the electrons to flow through, reducing collisions. A smaller cross section increases resistance as there is less space for the electrons to move, causing more collisions and therefore higher resistance.
Cell constant(C) = Resistance(R) X Specific Conductivity(K)
Resistance of a conductor is defined by the specific resistivity, area of cross section and the length of the conductor. R = rL/A, where R is resistance in OHMs, r is specific resistance, L length in mm, A is area of cross section in sq mm
Resistance of a conductor is defined by the specific resistivity, area of cross section and the length of the conductor. R = rL/A, where R is resistance in OHMs, r is specific resistance, L length in mm, A is area of cross section in sq mm
Resistance R =p(L /A)i,e Resistance(R) of a conductor will be directly proportional to its length(L) ==> if the length of the conductor increases its resistance also will increase.i,e Resistance(R) of a conductor is inversely proportional to its cross section area(A) ==> if the Area of the conductor increases its resistance also will decrease.
No. Resistance does.
As the length of an object increases, its electrical resistance also increases. This is because a longer object provides more path for the electrons to travel through, resulting in more collisions and a higher resistance to the flow of current. The relationship between length and resistance is directly proportional according to the formula R = ρ * (L/A), where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.
Resistance is inversely proportional to cross-sectional area. so ,if the thickness of the wire increases, the area of cross-section increases and this results in decrease of the resistance. The resistance R = l p / A where R is the resistance, l is the length of the wire, p(rho) is the electrical resistivity of the material and A is the area of cross section. So R the resistance is inversely proportional to A the area of cross-section. If R increases
The amount of air resistance an object has depends on it's shape and it's frontal cross-section.
The resistance of a wire is the length divided by the cross-section area and the conductivity of the material. So for small resistance you need a wire with short length, large cross-section area (diameter) and a material with high conductivity like copper.