* Multiples of 3 below 1000 range from 1 x 3 = 3 to 333 x 3 = 999. The average of all these is (3+999)/2 = 501. The total is therefore: 501 x 333 = 166833. * Multiples of 5 below 1000 range from 1 x 5 = 5 to 199 x 5 = 995. The average of all these is (5+995)/2 = 500. The total is therefore: 500 x 199 = 99500. As things stand we have counted the multiples of 15 (which divide by both 3 and 5) twice, so the whole set of them must be subtracted once: * Multiples of 15 below 1000 range from 1 x 15 = 15 to 66 x 15 = 990. The average of all these is (15+990)/2 = 502.5. The total is therefore: 502.5 x 66 = 33165. The grand total is 166833 + 99500 - 33165 = 233168
There are no multiples of 7 down there, nor are there any NON-multiples of 7 . The truth is that there are no numbers at all below.
Oh, what a happy little question! To find the multiples of 4 and 6 below one thousand, we need to see how many times each number fits into 1000. For 4, we divide 1000 by 4 to get 250 multiples. For 6, we divide 1000 by 6 to get 166 multiples. But wait, we've counted the multiples of 24 twice, so we need to subtract those extras to find the total number of unique multiples.
The numbers 1001 to 1999 add "one thousand" in front of the three-digit numbers 1 to 999. The number 2000 is "two thousand." See the related question (1 to 1000) below.
All but 251 of them. Any odd number greater than 1 can be written in the form 2n + 1 where n = 1,2,3,... then 2n+1 = (n + 1)2 - n2 Any multiple of 4 can be written as 4n where n = 1,2,3,... then 4n = (n + 1)2 - (n - 1)2 However, unless you allow 1 = 12 - 02 1 cannot be so written as a difference of two squares and odd multiples of 2 cannot be so written. So that is the number 1 and 250 odd multiples of 2: 251 numbers in all. 1 cannot be so written.
Common multiples of 4 and 6 below 1000: Lowest common multiple of 4 and 6 is 12 All multiples of 12 number 83 from 12 upto 996 because 1000/12 equals 83....
There are no multiples of 7 down there, nor are there any NON-multiples of 7 . The truth is that there are no numbers at all below.
Difficult to answer without knowing the numbers below. Choose multiples of 4. They will be even numbers.
Oh, what a happy little question! To find the multiples of 4 and 6 below one thousand, we need to see how many times each number fits into 1000. For 4, we divide 1000 by 4 to get 250 multiples. For 6, we divide 1000 by 6 to get 166 multiples. But wait, we've counted the multiples of 24 twice, so we need to subtract those extras to find the total number of unique multiples.
30, 60, 90
if it is even numbers they are 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48. but if it is even multiples of 50 there are none below 50
The numbers 1001 to 1999 add "one thousand" in front of the three-digit numbers 1 to 999. The number 2000 is "two thousand." See the related question (1 to 1000) below.
The sum of all multiples of 3 below 500 is the sum of 3 + 6 + ... + 498 = 41583The sum of all multiples of 5 below 500 is the sum of 5 + 10 + ... + 495 = 24750Depending upon the interpretation of "of 3 and 5", the answer is one of:The sum of all multiples of both 3 and 5 below 500 is the sum of 15 + 30 + ... + 495 = 8415The sum of all multiples of 3 below 500 and all multiples of 5 below 500 is 41583 + 24750 = 66333Since the multiples of both 3 and 5 (that is 15, 30, ...) have been counted twice - once in the multiples of 3 and once in the multiples of 5 - the sum of all multiples of 3 or 5 or both below 500 is 41583 + 24750 - 8415 = 57918I have emphasised the word below with regard to 500 since 500 is a multiple of 5, but 500 is not below (less than) itself, that is the multiples are of the numbers 1, 2, 3, ..., 499. If the question was intended to mean less than or equal to 500, add an extra 500 to the multiples of 5 above, making the sum of the multiples of 5 be 25250 and the final sums (1) 8415, (2) 66833, (3) 58418.
The answer given below is incorrect: 1 is NOT a multiple of 187. It is a factor, and that is a very different thing. Multiples of 187 are members of the infinite set of numbers of the form 187*k where k is an integer. Since the set is infinite, it is not possible to list them..
Fibonacci numbers appear in many natural contexts. Try the link below for a taste: it also gives a list of references if you wish to follow.
There are about 100 thousand different home remedies for arthritis go to the links below for more information on these.
All but 251 of them. Any odd number greater than 1 can be written in the form 2n + 1 where n = 1,2,3,... then 2n+1 = (n + 1)2 - n2 Any multiple of 4 can be written as 4n where n = 1,2,3,... then 4n = (n + 1)2 - (n - 1)2 However, unless you allow 1 = 12 - 02 1 cannot be so written as a difference of two squares and odd multiples of 2 cannot be so written. So that is the number 1 and 250 odd multiples of 2: 251 numbers in all. 1 cannot be so written.
8 of the numbers less than 660 are divisible by 5 and 11 but not 3. All numbers divisible by 5 and 11 are multiples of their lcm; lcm(5, 11) = 55 All numbers divisibile by 5, 11 and 3 are multiples of their lcm; lcm(5, 11, 3) = 165 659 ÷ 55 = 11 54/55 → 11 numbers less than 660 are divisible by 5 and 11 659 ÷ 165 = 3 164/165 → 3 numbers less than 660 are divisible by 5, 11 and 3 → of the 11 numbers less than 660 divisible by 5 and 11, 3 are also divisible by 3 → 11 - 3 = 8 numbers less than 660 are divisible by 5 and 11 but not 3,.