2n2 / n = 2n
The problem cannot be solved because there is no equation (or inequality) in the question: only three disjoint terms.
n squared minus six.
The power of a quotient is the quotient of the power! (a/b)^n = (a^n) / (b^n) where a/b is the quotient and n is the power.
n to the 3rd power is n x n x n
2n2 / n = 2n
The problem cannot be solved because there is no equation (or inequality) in the question: only three disjoint terms.
n squared minus six.
2*2*n2
Adding a capacitor in parallel with our load(inductive) this would make our voltage and currents in phase n hence a maximum power factor.
it is the same as adding a negative number to a positive number
The power required to exert a force of 1 N over a distance of 1 m in 1 second is 1 watt. This is because power is defined as the rate at which work is done, and in this case, the work done is 1 joule in 1 second.
The function t(n) relates to the function t(n1/2) 1 by taking the square root of n in the second function and adding 1 to the result.
less loud it takes the power and splits in half
If you put your second router next to the first one, the answer is no. You can put the second router in another part of building and create so called bridge which allows to increase coverage.
The power of a quotient is the quotient of the power! (a/b)^n = (a^n) / (b^n) where a/b is the quotient and n is the power.
The power expended to lift the 100 N box a distance of 2 meters in 1.0 second is 200 Watts. This is calculated by multiplying the force of 100 N by the distance of 2 meters divided by the time of 1.0 second.