Wiki User
∙ 9y agoIt may be that you don't have a "fair coin", or it might just be chance. To be sure - or rather, reasonably sure - you need to try tossing it quite a bit more times.
Wiki User
∙ 9y agoEmpirical apex students xp
The probability of NOT getting heads is (1/2)4=1/16 Therefore the probability of getting heads is 1-1/16=15/16
Possible outcomes are HH, HT, TH, TT; therefore the probability of HH is 1/4 or 0.25.
The probability of getting a head first time is one out of two, or a half. The probability of getting a head the next time is still one out of two, so the combined probability is one quarter. Similarly, one eighth is the probability of getting three in a row; but the pattern does not end there, the probability of getting a tails the next time is STILL one in two, so that is a one in sixteen chance of that run, the probability of the entire sequence is therefore one in thirty-two.
First calculate the probability of NOT getting a single 5. This probability is 5/6 x 5/6 = 25/36. Therefore, the probability of getting at least one 5 is the complement thereof, that is, 1 - 25/36 = 11/36.
Empirical apex students xp
The probability of NOT getting heads is (1/2)4=1/16 Therefore the probability of getting heads is 1-1/16=15/16
As the question is "what is the probability of getting at least one head" the correct way to answer this is to ask what is the probability of not getting any heads and then subtract this from 1.The probability of not getting a head in 4 flips = 0.54 (i.e. 0.5 * 0.5 * 0.5 * 0.5) = 1/16.Therefore the probability of getting at least one head is 1 - 1/16 = 15/16.
Probability are the odds of something happening but has multiple answers. Such as probability of getting a 5 in a fair dice would be 1 out of 6 because there are 6 numbers on a dice altogether, and ONE chance of getting a 5 from the total of 6. Therefore, the probability of getting a 5 or any number from a dice would be 1/6.
Possible outcomes are HH, HT, TH, TT; therefore the probability of HH is 1/4 or 0.25.
The probability of getting a head first time is one out of two, or a half. The probability of getting a head the next time is still one out of two, so the combined probability is one quarter. Similarly, one eighth is the probability of getting three in a row; but the pattern does not end there, the probability of getting a tails the next time is STILL one in two, so that is a one in sixteen chance of that run, the probability of the entire sequence is therefore one in thirty-two.
This depends entirely on the genotype of the parents. The probability of getting a specific genotype is the probability of getting the correct allele from mother (1/2) multiplied by the probability of getting the correct allele from father (1/2) multiplied by the number of ways this can occur. The probability of getting a phenotype, if the phenotype is dominant, is the sum of the probability of getting two dominant alleles, and the probability of getting one dominant allele. If the phenotype is recessive, the probability is equal to the probability of getting two recessive alleles.
First calculate the probability of NOT getting a single 5. This probability is 5/6 x 5/6 = 25/36. Therefore, the probability of getting at least one 5 is the complement thereof, that is, 1 - 25/36 = 11/36.
There is no probability. Sorry.
The probability of getting the queen of hearts is 1 in 52, or about 0.01923. The probability of getting any queen is 4 in 52, or about 0.07692. The probability of getting any heart is 13 in 52, or exactly 0.25.
The probability is likely to be 1.
The probability is 25%. The probability of flipping a coin once and getting heads is 50%. In your example, you get heads twice -- over the course of 2 flips. So there are two 50% probabilities that you need to combine to get the probability for getting two heads in two flips. So turn 50% into a decimal --> 0.5 Multiply the two 50% probabilities together --> 0.5 x 0.5 = 0.25. Therefore, 0.25 or 25% is the probability of flipping a coin twice and getting heads both times.