|Any Number|+15
Ix^2 - 8I
It can be: 2x-25 or 25-2x or maybe the absolute value of (2x-25).
Replace each variables in the algebraic expression by its [known] value and calculate the value (ie evaluate) of the algebraic expression.
The algebraic expression for 25 less than a number ( d ) is ( d - 25 ). This indicates that you subtract 25 from the value of ( d ).
322
Ix^2 - 8I
It can be: 2x-25 or 25-2x or maybe the absolute value of (2x-25).
To find the value of an algebraic expression is to evaluate it.
Replace each variables in the algebraic expression by its [known] value and calculate the value (ie evaluate) of the algebraic expression.
When the value of a variable in an algebraic expression changes, the value of the expression can change.
The algebraic expression for 25 less than a number ( d ) is ( d - 25 ). This indicates that you subtract 25 from the value of ( d ).
The verbal expression that represents the algebraic expression 2x-8 is "twice a number decreased by 8." In this expression, "2x" represents twice the value of a variable "x," and "-8" indicates that 8 is being subtracted from that value. Therefore, "twice a number decreased by 8" accurately describes the algebraic expression 2x-8.
322
The answer to the question is given in the question!If you want to find the value of an algebraic expression, then you need to substitute numerical values for each of the variables in the expression, and then calculate and simplify the result.
A constant in an algebraic expression is a number that does not change. For example x + 2 The 2 is a constant (does not change) x is a variable (can take on any value)
Absolute value can be defined as the distance from the expression to zero. Therefore, the absolute value of 13 is 13.
Say you have an algebraic expression y = 3x +4 For a given value of x = 5 substitute that number in place of x in the expression, so in this case y = 3(5) + 4 = 19