I thinks that might be
r k r j s k s j t k
Repeats the sequence of the letter rr ss tt. . . . and k...j
... k ... j ... k ... j ... k ---> line 1
r......r.....s....s.....t.... ---> line 2
Match line 1 with line 2.
I hope it is clear and correct.
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%%%fim1 is our image%%% [ r c ] = size(fim1); even=zeros(r,(c/2)); %first level decomposition %one even dimension for j = 1:1:r a=2; for k =1:1:(c/2) even(j,k)=fim1(j,a); a=a+2; end end %one odd dim odd=zeros(r,(c/2)); for j = 1:1:r a=1; for k =1:1:(c/2) odd(j,k)=fim1(j,a); a=a+2; end end [ lenr lenc ]=size(odd) ; %one dim haar for j = 1:1:lenr for k =1:1:lenc fhigh(j,k)=odd(j,k)-even(j,k); flow(j,k)=even(j,k)+floor(fhigh(j,k)/2); end end %2nd dimension [len2r len2c ]=size(flow); for j = 1:1:(len2c) a=2; for k =1:1:(len2r/2) %even separation of one dim leven(k,j)=flow(a,j); heven(k,j)=fhigh(a,j); a=a+2; end end %odd separtion of one dim for j = 1:1:(len2c) a=1; for k =1:1:(len2r/2) lodd(k,j)=flow(a,j); hodd(k,j)=fhigh(a,j); a=a+2; end end %2d haar [ len12r len12c ]=size(lodd) ; for j = 1:1:len12r for k =1:1:len12c %2nd level hh f2lhigh(j,k)=lodd(j,k)-leven(j,k); %2nd level hl f2llow(j,k)=leven(j,k)+floor(f2lhigh(j,k)/2); %2nd level lh f2hhigh(j,k)=hodd(j,k)-heven(j,k); %2nd level ll f2hlow(j,k)=heven(j,k)+floor(f2hhigh(j,k)/2); end end % level=level-1;
C
It looks as if every third letter is an "r"; the remaining letters are in sequence.
A geometric sequence is a sequence of a number in which the ratio of any number (other than the first) to its predecessor (the one before) is a constant.if t(k) is the kth term in the sequence thent(1), the seed, is given and then,t(n) = r*t(n-1) where r is the common ratio.
It's the alphabet spaced by prime numbers: a+2=c, c+3=f, f+5=k, k+7=r, r+11 takes you past the end so start again at a = c.