Wiki User
∙ 14y agoSince the DENSITY of WATER = 1, and the Weight is 14 Newtons (in air) and 3 Newtons (Submerged in Water) we can figure the Density of the Object by the following:
N = kg·m/s2
14 N = (Mass of Object) x 9.81 m/s2
(Mass of Object) = 14 N / 9.81 m/s2
(Mass of Object) = 1.427 kg
And Since IN WATER the Object is 3 Newtons:
3 N = (1.427 kg x 9.81m/s2 ) / (Density of Object)
3 N = (14 N) / (Density of Object)
Density of Object = (14 N) / (3 N)
Density of Object = 4.6667
Wiki User
∙ 14y agoThey are equal.
Derive from measurements of length, breadth, height, radius, diameter etc. Measure the volume of displaced liquid when the object is submerged. If the object is of a material of known density (or specific gravity), weigh it and calculate volume from volume = mass/density.
yes
You haven't asked a question. So I'll ask one using your data, and then answer it. Q: What is the apparent weight of the object when it's completely submerged ? A: 5 N.
Object's density = (its mass) divided by (its volume)
Submerged density is the density of an object when it is immersed in a fluid. It takes into account the volume of the object that is submerged in the fluid. This can be calculated using the formula: (density of object * volume of object) / (volume of object - volume of displaced fluid).
mass of fluid, weight of fluid, density of fluid.
An object will appear to lose weight when completely submerged in water due to the buoyant force acting on it. This force is equal to the weight of the water displaced by the object, causing it to feel lighter in water compared to in air.
When an object is immersed in water, it means it is completely surrounded or covered by the water.
The milliliters of a completely submerged object is equal to the milliliters of water displaced. This is in line with Archimedes' principle, which states that the volume of water displaced by an object is equal to the volume of the object submerged.
The buoyancy of an object depends on its density compared to the density of the fluid it is submerged in. If the object's density is less than the fluid, it will float; if the density is greater, it will sink. The lower the density of the object, the higher the buoyant force acting on it.
the buoyant force acting on the object is greater than its weight. This occurs when the density of the object is less than the density of the fluid it is submerged in.
The two ways to measure the density of an object are by using its mass and volume. You can calculate density by dividing the object's mass by its volume, or by measuring the displacement of water when the object is submerged in it.
The density of the liquid affects the buoyancy of an object by determining how much force the liquid exerts on the object. If the liquid is more dense than the object, the object will float. If the object is more dense than the liquid, the object will sink.
When the buoyant force on a submerged object is equal to the weight of the object, the density of the object is equal to the density of the water. This is because for the buoyant force to equal the weight of the object, the object displaces its own weight of water, which can only happen if the object and the water have the same density.
The buoyant force exerted on an object submerged in water is determined by the object's volume and the density of the fluid it is in. Specifically, the buoyant force is equal to the weight of the fluid that the object displaces.
If the solid is not completely submerged in the water, the volume of water displaced will be underestimated. This error will lead to a lower apparent volume, resulting in a higher reported density of the solid than the true value.