-4 + 2y = 242y + 4 = 242y + 4 - 4 = 24 - 42y + 4 - 4 = 24 - 42y = 24 - 42y = 202y/2 = 20/22y/2 = 20/2y = 20/2y = 10Therefore the y-intercept is at (0,10) or has a value of 10
Inconsistent linear equations in two variables.
When x = -2 then y = 4 which is the common point of intersection of the two equations.
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
x = 4 and y = 0
-4 + 2y = 242y + 4 = 242y + 4 - 4 = 24 - 42y + 4 - 4 = 24 - 42y = 24 - 42y = 202y/2 = 20/22y/2 = 20/2y = 20/2y = 10Therefore the y-intercept is at (0,10) or has a value of 10
Inconsistent linear equations in two variables.
When x = -2 then y = 4 which is the common point of intersection of the two equations.
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
x=3
The ordered pair is (1, 3).
x = 4 and y = 0
Two equations: a linear one in y and a quadratic in x.
There are two equations in the question, not one. They are the equations of intersected lines, and their point of intersection is their common solution.
Indeed, these two equations are the same - because addition is a commutative function.
2y + 3 = 42y = 4 - 32y = 1divide both sides of the equation by 22y/2 = 1/2y = 1/2 in fractionory = 0.50 in decimal
a=5: c=4