2x2 + x2 = 3x2
x2 + x2 = 2x2 2x^2
2x2 + (5x-4x)2 + (x-x)2 = 2x2 + x2 + 02 = 2x2 + x2 = 3x2
If: x2+2x-3 = 0 Then: x = 1 or x = -3
x2+2x-120 = (x+12)(x-10) when factored
-x2+2x
2x2 + x2 = 3x2
x2 + x2 = 2x2 2x^2
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
Factor it out: (x+2) squared
2x2 + (5x-4x)2 + (x-x)2 = 2x2 + x2 + 02 = 2x2 + x2 = 3x2
17
x2
If: x2+2x-3 = 0 Then: x = 1 or x = -3
x2+2x-120 = (x+12)(x-10) when factored
x2 - (2x)2 = x2 - 4x2 = -3x2 x2 - 2x2 = -x2
If you mean: x2+2x+1 = 0 then it is a quadratiic equations whose solutions are equal because x = -1 and x = -1