well there's three answers to this question one of them is one and the other two are roots of a quadratic equation that include the imaginary number i.
forgot the exact answers but i remember that you have to factor x^3-1
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One because if x3 = 1 then x must equal 1
If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator
x=4.
That's the same as x3 times x3 which equals x6
Subtract 1 from each side: x3 = 64; You might know that 4 cubed is 64, but if you don't then take log 64, divide it by 3 and take the antilog of your answer...