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How many complex roots does 6x4 plus x3 - 5 equals 0 have?
It has two complex roots.
What are the roots of 1 minus x to the third power?
The roots of 1 - x3 are 1 - x and 1 + x + x2, by application of the difference-of-cubes formula.
What is x3-x2-x minus 2 factored?
x3-x2
What are the zeros of this polynomial function f of x equals x3 minus 3x2 minus 5x plus 39?
f(x)=x3-3x2-5x+39=(x+3)(x2-6x+13) It has three roots. One of which is x=-3. Using the quadratic equation: x = (6 +/- √(-16))/2 x = (6 +/- 4i)/2 = (3 +/- 2i) so, x=-3, x=3+2i, or x=3-2i
Insert two parenthesis 10 minus 4 divided by 2 X 3 equals 24?
(10-4/2)x3=24
What are the real roots of x5 - 2x4 - 24x3 equals 0?
x5 - 2x4 - 24x3 = 0 x3(x2 - 2x - 24) = 0 x3(x2 + 4x - 6x - 24) = 0 x3(x - 6)(x + 4) = 0 x = {-4, 0, 6}
What is the answer to x4 plus x3 minus 14x2 plus 4x plus 6 divided by x minus 3?
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
What are the roots of 1 minus x cubed?
1 - x3 = (1 - x)(1 + x + x2) So the roots are 1 (the root of 1 - x) and [-1 +/- sqrt(-3)]/2 (the roots of x2 + x + 1, via the quadratic formula. Note: Sqrt means "square root", and +/- means "plus-or-minus". This site has no easy access to those symbols.
What is x cubed minus 4 x squared plus 7 x divided by x equals?
[ x3 - 4x2 + 7x ] / (x) = x2 - 4x + 7
What are the roots of x3 plus 3x2-9x plus 5?
x3 + 3x2 - 9x + 5 = 0 has roots of -5,1 and 1. CHECK : x3 + 3x2 - 9x + 5 = (x + 5)(x - 1)(x - 1)
How do you solve x cubed minus 4 equals 2?
x3-4=2 Add four to both sides. x3=6 Take the cu=6 be root of both sides. x is equal to the cube root of 6, or approximately 1.81712.
How do you solve x³-4x equals 0 algebraically?
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
