3 4 5 6 8 10 9 40 41 20 21 29 9 12 15 ...and factors of those such as the first 2 examples.
To determine if 9, 15, and 12 form a Pythagorean triple, we check if the square of the largest number equals the sum of the squares of the other two. Here, 15 is the largest number. Calculating, we have (15^2 = 225) and (9^2 + 12^2 = 81 + 144 = 225). Since both sides are equal, 9, 15, and 12 do form a Pythagorean triple.
-2 (negative 2)11 less than 9:= 9 - 11= -2
No
Average: (13+9)/2 = 11
Yes
From the Pythagorean Theorem: c^2 = a^2 + b^2. So,c = √(a^2 + b^2) substitute the given values:c = √(4^2 + 3^2)c = √(16 + 9)c = √25c = 5 (since the length is always positive)One of the Pythagorean triples is 3,4,5. So, if you know all the Pythagorean triples, you don't need to do the computations above.The Pythagorean triple: A set of three positive integers a, b, and c such that a^2 + b^2 = c^2. Pythagorean triples that have greatest common divisor equal to 1 include the following: {3, 4, 5}, {5,12, 13}, {8, 15, 17}, {7, 24, 25}, and {20, 21, 29}.
3 4 5 6 8 10 9 40 41 20 21 29 9 12 15 ...and factors of those such as the first 2 examples.
The Pythagorean thereom is a^2+b^2=c^2. So, you can tell if they are a Pythagorean triple by seeing if the two smaller numbers squared equal the largest number squared. Example. Are 3,4, and 5 a Pythagorean triple? 3^2= 9. 4^2= 16. 5^2= 25. 9+16=25, so they are a triple.
15, since 15*2 = 9*2 + 12*2
3 4 5 6 8 10 9 40 41 20 21 29 9 12 15 ...and factors of those such as the first 2 examples.
-2
2 + 2 + 9 = 13
diagonal="c" side=9="9"="9" sincec^2=b^2+a^2, diagonal=square root of(2(9^2))=
-2 (negative 2)11 less than 9:= 9 - 11= -2
Yes; for example (9, 12, 15) can not be found. However, all primitive triples are found.
20