3 4 5 6 8 10 9 40 41 20 21 29 9 12 15 ...and factors of those such as the first 2 examples.
-2 (negative 2)11 less than 9:= 9 - 11= -2
No
Average: (13+9)/2 = 11
-97
Yes
From the Pythagorean Theorem: c^2 = a^2 + b^2. So,c = √(a^2 + b^2) substitute the given values:c = √(4^2 + 3^2)c = √(16 + 9)c = √25c = 5 (since the length is always positive)One of the Pythagorean triples is 3,4,5. So, if you know all the Pythagorean triples, you don't need to do the computations above.The Pythagorean triple: A set of three positive integers a, b, and c such that a^2 + b^2 = c^2. Pythagorean triples that have greatest common divisor equal to 1 include the following: {3, 4, 5}, {5,12, 13}, {8, 15, 17}, {7, 24, 25}, and {20, 21, 29}.
3 4 5 6 8 10 9 40 41 20 21 29 9 12 15 ...and factors of those such as the first 2 examples.
The Pythagorean thereom is a^2+b^2=c^2. So, you can tell if they are a Pythagorean triple by seeing if the two smaller numbers squared equal the largest number squared. Example. Are 3,4, and 5 a Pythagorean triple? 3^2= 9. 4^2= 16. 5^2= 25. 9+16=25, so they are a triple.
3 4 5 6 8 10 9 40 41 20 21 29 9 12 15 ...and factors of those such as the first 2 examples.
15, since 15*2 = 9*2 + 12*2
-2
2 + 2 + 9 = 13
diagonal="c" side=9="9"="9" sincec^2=b^2+a^2, diagonal=square root of(2(9^2))=
Yes; for example (9, 12, 15) can not be found. However, all primitive triples are found.
-2 (negative 2)11 less than 9:= 9 - 11= -2
20