Yes.
figure
Each point can be connected to every other point. That gives you 10 x 9. However, since this counts each line segment twice, this result should be divided by 2.
In the English alphabet, the uppercase letters that have perpendicular line segments are A, B, D, E, F, H, K, L, T, and Z. This totals to 10 uppercase letters. Each of these letters includes at least one pair of line segments that meet at a right angle.
To create a row of 6 triangles, each triangle can be formed using 3 line segments. However, since the triangles share sides, the total number of segments needed will be fewer than 18 (6 triangles × 3 segments each). Specifically, for 6 triangles arranged in a row, you need 10 segments: 3 for the first triangle, 1 additional for each of the 5 shared sides between the triangles, and 3 for the last triangle. Thus, the total number of line segments needed is 15.
To determine how many 3 dm segments fit into 10 dm, you divide 10 by 3. This calculation gives you approximately 3.33. Therefore, you can fit three full 3 dm segments into 10 dm, with a remainder of 1 dm.
11
10 collinear points form one set of overlapping line segments, of which there are 45.
figure
Each point can be connected to every other point. That gives you 10 x 9. However, since this counts each line segment twice, this result should be divided by 2.
In the English alphabet, the uppercase letters that have perpendicular line segments are A, B, D, E, F, H, K, L, T, and Z. This totals to 10 uppercase letters. Each of these letters includes at least one pair of line segments that meet at a right angle.
The sum is 6.
You need any number between 10 to 20 distinct end points.
There are 10 segments of 0.3 centimeters each in 3 centimeters. You can divide 3 by 0.3 to get the answer.
You need any number between 10 to 20 distinct end points.
Points:(4, 3) and (10, -5) Midpoint: (4+10)/2, (3-5)/2 = (7, -1)
8:58:58 - i think so.
All crustaceans have 10 legs, 2 body segments, and 1 pair of antennae.