No.
All it needs is one counter example to disprove: 6 is a multiple of 2 but NOT a multiple of 4.
They are all the multiples of 4.
Yes.
Since 8 is a multiple of 2 and 4, all multiples of 8 are also multiples of both of them. Thus, Jose and maria are both correct.
They are all multiples of 1 and 2.
2, 4, 6, 8, 10.
They are all the multiples of 4.
All multiples of 4 are multiples of 2 and 4.
It's not. 4 is a multiple of 2. 2 is a factor of 4 because it can divide into 4 evenly with no remainder.
Yes. In fact all even numbers (not just 4) will share their multiples with 2.
Yes.
Since 4 is a multiple of 2, all the multiples of 4 will be common.
Because 6 is a multiple of 2 and not of 4.
Because 20 is a multiple of 4. All multiples of 20 are also multipples of 2, 5 and 10
all numbers that are multiples of 4 have 2 as factor
Any and all multiples of 60.
Since 8 is a multiple of 2 and 4, all multiples of 8 are also multiples of both of them. Thus, Jose and maria are both correct.
If ordered by size, only every other multiple of 2 is a multiple of 4. All multiples of 4 are multiples of 2.