2 and 5 are the prime factors that are common to all multiples of 10.
10, and all its multiples.
All multiples of 10.
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40 -2,-4,-6,-8,-10 All the even numbers are multiples of 2 here are some negatives also count.
They are all multiples of 1 and 2.
2 and 5 are the prime factors that are common to all multiples of 10.
10, and all its multiples.
All multiples of 10.
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40 -2,-4,-6,-8,-10 All the even numbers are multiples of 2 here are some negatives also count.
Because 20 is a multiple of 4. All multiples of 20 are also multipples of 2, 5 and 10
The multiples of 10 are: 1, 2, 5, 10 The multiples of 5 are: 1 and 5. The multiples of 6 are: 1, 2, 3, and 6. The multiples of 8 are: 1, 2, 4, and 8. The number that they all have in common is 1, so the lcd is one.
2 and 5
2 and 5
They are all multiples of 1 and 2.
All of the multiples of 10 are even.
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100
The common multiples of 2 and 5 are 10, 20, 30, 40, etc.In detail:A common multiple is a number divisible by both (or all) numbers: 2 and 5, here.Knowing that all numbers divisible by 2 have a 0, 2, 4, 6, or 8 in the ones place combined with the knowledge that all numbers divisible by 5 end with 0 or 5 (excluding 0 in both cases), we can say the only multiples of each number that are common to both are numbers that end with 0.Another way of analyzing this problem is to say that both 5 and 2 are factors. 10 is clearly a multiple of 5 and 2 because 2(5)=10. Any number divisible by 10 is thus also divisible by 2 and 5. All numbers divisible by 10 end in 0. Thus, a number ends in 0 if and only if it is divisible by 2 and 5.Answer: Common multiples of 2 and 5 end with zero.