Yes. If a number is evenly divisible by both 3 and 4, it will also be divisible by 6.
This is because the prime factor of 3 is [3] -- in other words, 3 is a Prime number -- and the prime factors of 4 are [2, 2].
Thus, any number that is divisible by 3 and 4 will have as part of its prime factors the set [2, 2, 3]. (The smallest such number is 12, which is 2 x 2 x 3.) Since the prime factors of 6 are [2, 3] -- and [2, 3] is a subset of [2, 2, 3] -- then any such number must also be divisible by 6.
Another way to look at it is to note that all numbers which are divisible by both 3 and 4 are also divisible by 12 (which is 3 x 4). Since 12 is divisible by 6, then all multiples of 12 will also be divisible by 6.
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
All 4 digit numbers that are divisible by 9 are also divisible by 3. The first is 1008 and the last is 9999.
All numbers of the form 6+12x are, for all integer x.
All numbers that are divisible by 8 and 12 would also be divisible by 4.
no, 18 is divisible by 9 but not by 4.
12 is the Lowest Common Multiple
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
All 4 digit numbers that are divisible by 9 are also divisible by 3. The first is 1008 and the last is 9999.
12 and all multiples of 12.
All numbers of the form 6+12x are, for all integer x.
All numbers that are divisible by 6 are even numbers whose digits add up to 3 or a multiple of 3. Example : 284 is not wholly divisible by 6 as although it is even, its digits total 2 + 8 + 4 = 14 which is not divisible by 3. 282 is divisible by 6 as it is even and its digits total 12 which is divisible by 3.
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
2: 2,4,6,8,10,12,14,16,18,20...4: 4,8,12,16,20,24,28,32,36,40...Half of all numbers divisible by 2 are divisible by 4.All numbers divisible by 4 are divisible by 2.
All numbers that are divisible by 8 and 12 would also be divisible by 4.
They are divisible by 2, 3, 4, 5, 6, 10, 12, 15, 30 and 60 at least.
0,12,24,36,48,60,72,84, and 96 are the numbers between 0 and 100 that are divisible by both 3 and 4.
no, 18 is divisible by 9 but not by 4.