Yes. If the integers making up the number add to a number divisible by 3, then it is divisible by 3.The integers 34215 add up to 15, so it is divisible by 3.34215/3 = 11405
Any number whose sum of its digits are equal to a multiple of 3, is divisible by 3. In this instance, the sum of the digits of the number 34215 is equal to 15, which is divisible by 3, and therefore the number is divisible by 3.
If a number is even (divisible by 2) and divisible by 3, then it must also be divisible by 6.
False. The question consists of two parts: - a number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. - a number is divisible by 6 only if it is divisible by 3? This is true but the false part makes the whole statement false.
3924 is divisible by 3 as the digits added together 3+9+2+4=18 is divisible by 3
Yes. If the integers making up the number add to a number divisible by 3, then it is divisible by 3.The integers 34215 add up to 15, so it is divisible by 3.34215/3 = 11405
Any number whose sum of its digits are equal to a multiple of 3, is divisible by 3. In this instance, the sum of the digits of the number 34215 is equal to 15, which is divisible by 3, and therefore the number is divisible by 3.
True fact.
If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.
Yes, it is true 558/3 = 186 To find out if a number is divisible by 3, add the digits; if the sum is divisible by 3, so is the number 5+5+8 = 18 which is divisible by 3
Yes. The sum of the digits is 18 which is divisible by 3.
True. Since 615 ends in 5, it is divisible by 5. Since the sum 12, of the digits of 615, is divisible evenly by 3, 615 is divisible by 3.
If a number is even (divisible by 2) and divisible by 3, then it must also be divisible by 6.
3924 is divisible by 3 as the digits added together 3+9+2+4=18 is divisible by 3
False. The question consists of two parts: - a number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. - a number is divisible by 6 only if it is divisible by 3? This is true but the false part makes the whole statement false.
How can the following definition be written correctly as a biconditional statement? An odd integer is an integer that is not divisible by two. (A+ answer) An integer is odd if and only if it is not divisible by two
yes