Yes it is true.
If you add up the sum of all of the numbers in 34215 like this: 3+4+2+1+5, they equal to 15.
15 is a number that is divisible by 3.
This strategy works for all numbers.
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Yes, 34215 is divisible by 3 because the sum of its digits (3 + 4 + 2 + 1 + 5 = 15) is divisible by 3.
Yes. If the integers making up the number add to a number divisible by 3, then it is divisible by 3.The integers 34215 add up to 15, so it is divisible by 3.34215/3 = 11405
Any number whose sum of its digits are equal to a multiple of 3, is divisible by 3. In this instance, the sum of the digits of the number 34215 is equal to 15, which is divisible by 3, and therefore the number is divisible by 3.
If a number is even (divisible by 2) and divisible by 3, then it must also be divisible by 6.
3924 is divisible by 3 as the digits added together 3+9+2+4=18 is divisible by 3
False. The question consists of two parts: - a number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. - a number is divisible by 6 only if it is divisible by 3? This is true but the false part makes the whole statement false.