All of them. 1,2,5 and 10.
all even factors of 88 are 2*2*2 so some of these factors is 6.
48 has both even and odd factors.
The factors of 10 are 1, 2, 5 and 10. For them to be common, they need to be compared to another set of factors.
2 and 5 are the prime factors that are common to all multiples of 10.
2 and 10
The factors of 10 are: 1, 2, 5, 10
they are 2 , 10 and 18
All of the factors of 12 are 1,2,3,4,6,12. Therefore, the even factors must be 2,4,6,12.
1 and 2 are factors of all even numbers.
48 is the lowest of all whole numbers having 10 factors.
1, 2, 5 and 10.
The common factors are: 1, 2, 5, 10.
Listing all of the factors of 60 we get: 1 2 3 4 5 6 10 12 15 20 30 Then removing the even factors, we are left with: 1 3 5 and 15.
Every one of them has an even number of factors.
The answer to the question is: "All of the common factors of 10, 25, and 20 are 1 and 5 ."
All even numbers greater than 2 have even proper factors, since they all have 2 as a proper factor.