All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.
For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.
54 is divisible by 1, 2, 3, 6, 9, 18, 27, 54 Multiples of 54 are divisible by 54.
6 and its multiples are divisible by 2 and 3.
Itself and any multiples of 9
yes since 9 is divisible by 3 all its multiples are as well
The common multiples of 3 and 9 are 9, 18, 27 and so on.Any number that is divisible by 9 is also divisible by 3. This is because 9 is divisible by 3, so any multiples of 9 must also be divisible by three.78 117 156 195 234 273 312 351 390and so on ...
All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.
All multiples of 18 are divisible by 9. Not all multiples of 9 are divisible by 18.
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
All multiples of 3, which is an infinite number, including 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33 . . .
yes, at least until the multiple of 12
Every one of the infinite number of multiples of 9 is, as well as roughly 1/3 of the multiples of 3. There sure are a huge number of them.
For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.
54 is divisible by 1, 2, 3, 6, 9, 18, 27, 54 Multiples of 54 are divisible by 54.
yes * * * * * Absolutely not! If it is divisible by 9 it must be divisible by 3. Here, if you want it, is a proof: x is divisible by 9 implies that x = 9*y for some integer y. Now 9 = 3*3, so writing 3*3 instead of 9 gives x = (3*3)*y so, by the associative property of multiplication, x = 3*(3*y) and then, by the closure of multiplication of integers, 3*y is also an integer. Say, z, for example. That is to say, x = 3*z which is equivalent to saying that x is divisible by 3.
6 and its multiples are divisible by 2 and 3.