No.
No.
Rational numbers are numbers that can be expressed as a fraction a/b where a and b are both integers and b is not equal to zero. All integers n are rational numbers because they can be expressed as the fraction n/1. Rational numbers are closed under addition, subtraction, multiplication and division by a non-zero rational. To be closed under addition, subtraction, multiplication and division by a non-zero rational means that if you have two rational numbers, when you add, subtract, multiple or divide them, you will get another rational number. For example, take the rationals 1/3 and 4/3. When you add them together, you get another rational number, 5/3. Same with the other operations. 1/3 - 4/3 = -1 (remember integers are rational, too) (1/3) * (4/3) = 4/9 (1/3) / (4/3) = 1/4
Division (by 2).
An expression produces a rational number when its value can be expressed as a fraction ( \frac{a}{b} ), where ( a ) and ( b ) are integers and ( b \neq 0 ). For example, the expression ( 3 + 2 ) evaluates to ( 5 ), which is rational, as it can be represented as ( \frac{5}{1} ). Similarly, any expression involving addition, subtraction, multiplication, or division of rational numbers (as long as division by zero is avoided) will yield a rational result.
Because when one rational number is subtracted from another rational number the result is a rational number. Don't forget that integers (ℤ) are a subset of rational numbers (ℚ).
Any addition, subtraction, multiplication, or division of rational numbers gives you a rational result. You can consider 8 over 9 as the division of 8 by 9, so the result is rational.
you can not use commutative property for subtraction because if you switch them around you will end up with a negative number.
when we add and substract any number * * * * * "substract" is not a word, and in any case, subtraction is not commutative. A binary operation ~, acting on a set, S, is commutative if for any two elements x, and y belonging to S, x ~ y = y ~ x Common binary commutative operations are addition and multiplication (of numbers) but not subtraction nor division.
No.
It is 0.
Rational numbers are numbers that can be expressed as a fraction a/b where a and b are both integers and b is not equal to zero. All integers n are rational numbers because they can be expressed as the fraction n/1. Rational numbers are closed under addition, subtraction, multiplication and division by a non-zero rational. To be closed under addition, subtraction, multiplication and division by a non-zero rational means that if you have two rational numbers, when you add, subtract, multiple or divide them, you will get another rational number. For example, take the rationals 1/3 and 4/3. When you add them together, you get another rational number, 5/3. Same with the other operations. 1/3 - 4/3 = -1 (remember integers are rational, too) (1/3) * (4/3) = 4/9 (1/3) / (4/3) = 1/4
Division (by 2).
An expression produces a rational number when its value can be expressed as a fraction ( \frac{a}{b} ), where ( a ) and ( b ) are integers and ( b \neq 0 ). For example, the expression ( 3 + 2 ) evaluates to ( 5 ), which is rational, as it can be represented as ( \frac{5}{1} ). Similarly, any expression involving addition, subtraction, multiplication, or division of rational numbers (as long as division by zero is avoided) will yield a rational result.
Because when one rational number is subtracted from another rational number the result is a rational number. Don't forget that integers (ℤ) are a subset of rational numbers (ℚ).
an algebraic expression is an expression built up from constants, variables, and a finite number of algebraic operations (addition, subtraction, multiplication,division and exponentiation to a power that is a rational number). For example,
Who knows - there appears to be no such word as communative! So maybe it is communative and maybe it is not.If, however, you meant commutative which, is a mathematical term, then the answer is no, subtraction is not commutative.
Yes. The rational numbers are a closed set with respect to subtraction.