But if a number is divisible only by itself and by 1, then it is prime. So, because all the other even numbers are divisible by themselves, by 1, and by 2, they are all composite (just as all the positive multiples of 3, except 3, itself, are composite).
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No number that is a multiple of 3, can be a prime number. A prime number must only be divisible by itself and 1. It cannot be divisible by any other number. Therefore if it is a multiple of 3, then it must be divisible by 3 and hence, not a prime number.
No, because it is divisible by 3 and 11111. A prime number can only be divisible by 1 and itself.
Three is a prime number and isn't divisible by any whole number * * * * * True, but irrelevant to the question. Any number that is divisible by 10 MUST be divisible by 5. Therefore there are no such numbers.
The number 45 is not a prime. It can be divided by 3 and 5. The number 5 is prime, and any number ending in 5 is divisible by 5 and will not be prime for that reason.
There are no prime numbers divisible by 435. 435 is divisible by 3, 5 and 29