No number that is a multiple of 3, can be a prime number. A prime number must only be divisible by itself and 1. It cannot be divisible by any other number. Therefore if it is a multiple of 3, then it must be divisible by 3 and hence, not a prime number.
No, because it is divisible by 3 and 11111. A prime number can only be divisible by 1 and itself.
Three is a prime number and isn't divisible by any whole number * * * * * True, but irrelevant to the question. Any number that is divisible by 10 MUST be divisible by 5. Therefore there are no such numbers.
The number 45 is not a prime. It can be divided by 3 and 5. The number 5 is prime, and any number ending in 5 is divisible by 5 and will not be prime for that reason.
Yes. If a number is evenly divisible by both 3 and 4, it will also be divisible by 6.This is because the prime factor of 3 is [3] -- in other words, 3 is a prime number -- and the prime factors of 4 are [2, 2].Thus, any number that is divisible by 3 and 4 will have as part of its prime factors the set [2, 2, 3]. (The smallest such number is 12, which is 2 x 2 x 3.) Since the prime factors of 6 are [2, 3] -- and [2, 3] is a subset of [2, 2, 3] -- then any such number must also be divisible by 6.Another way to look at it is to note that all numbers which are divisible by both 3 and 4 are also divisible by 12 (which is 3 x 4). Since 12 is divisible by 6, then all multiples of 12 will also be divisible by 6.
Prime numbers are only divisible by 1 and themselves. Since 3 is not a prime number, any prime number divisible by 3 does not exist. Therefore, the set of prime numbers divisible by 3 is an empty set.
No number that is a multiple of 3, can be a prime number. A prime number must only be divisible by itself and 1. It cannot be divisible by any other number. Therefore if it is a multiple of 3, then it must be divisible by 3 and hence, not a prime number.
A prime number is any integer evenly divisible by only itself, and the number 1. Since 21 is divisible by 3 and 7, it is a composite number, not a prime number.No, 21 is not a prime number.21 is divisible by 1, 3, 7, & 21No. 21=3*7
No, because it is divisible by 3 and 11111. A prime number can only be divisible by 1 and itself.
3 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.
Because any number divisible by 2 is not a prime number, so any even no. is divisible by 2. Thus any number higher than 3 will be divisible by 2. Therefore the only consecutive prime nos. are 1, 2 and 3
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
It is divisible by any real number. It is divisible evenly by 2, 3, 5 and 419, all prime.
Three is a prime number and isn't divisible by any whole number * * * * * True, but irrelevant to the question. Any number that is divisible by 10 MUST be divisible by 5. Therefore there are no such numbers.
No, this number is divisible by 3 and hence is not a prime number. You can tell that fast by adding the individual digits. If that sum is itself divisible by 3, as this one is, then the number itself is divisible by 3.
No, 1851 is not a prime number as it is divisible by 3.
The number 45 is not a prime. It can be divided by 3 and 5. The number 5 is prime, and any number ending in 5 is divisible by 5 and will not be prime for that reason.