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Q: Assuming the sequences are all equally likely what is the probability that you will get exactly two heads when you toss a coin three times?

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The answer is 1/2 , assuming the coin is fair.

The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.

P(3a) = 5c3 ∙(0.61)3∙(0.39)2 = 0.3452... ~ 34.5%

The probability is 2 - 6

The probability is 0.375

Related questions

50-50

A computer is programmed to generate a sequence of three digits, where each digit is either 0 or 1, and each of these is equally likely to occur. Construct a sample space that shows all possible three-digit sequences of 0s and 1s and then find the probability that a sequence will contain exactly one 0.

The answer is 1/2 , assuming the coin is fair.

A computer is programmed to generate a sequence of three digits, where each digit is either 0 or 1, and each of these is equally likely to occur. Construct a sample space that shows all possible three-digit sequences of 0s and 1s and then find the probability that a sequence will contain exactly one 0.

The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.

P(3a) = 5c3 ∙(0.61)3∙(0.39)2 = 0.3452... ~ 34.5%

Assuming we want two tails exactly, the possible options to get them are: TTH, THT and HTT. They are three choices out of the eight available, which is a probability of 3/8, 0.375 or 37.5%.

The probability is 2 - 6

The probability is 0.375

If you mean 'at least' 2 heads, the probability is 50%. If you mean exactly 2, the probability is 3/8, or 37.5%. There are 3 independent coin tosses, each of which is equally likely to come up heads or tails. That's a total of 2 * 2 * 2 or 8 possible outcomes (HHH, HHT, HTH, etc.). Of these, 4 include 2 or 3 heads, which is half of 8. Only 3 include exactly 2 heads, so the probability of that is 3/8.

.125

The probability of getting exactly eight heads when tossing 10 coins once can be found using the binomial probability formula. Assuming a fair coin, the probability of getting a heads is 1/2. Plugging in the numbers, the probability of getting exactly eight heads is (10 choose 8) * (1/2)^8 * (1/2)^2 = 45/1024, which is approximately 0.04395.