(6, 0) and (0, 8)
From what i understand the equation is like this; (3 * 2 ) + 6x + 24 = 0 6 + 6x +24 = 0 6x = - 24 - 6 6x = - 30 x = - 5
8x + 32 + 24 = 0 So 8x + 56 = 0 Subtract 56 from both sides: 8x = -56 Divide both sides by 8: x = -7
Yes because if 1+0=1 than 0 plus b equals b
It can be simplified in the form of: 2x3+9x2-7x-34 = 0
2z+6z+24=0 8z+24=0 8z= -24 z= - 3
(6, 0) and (0, 8)
From what i understand the equation is like this; (3 * 2 ) + 6x + 24 = 0 6 + 6x +24 = 0 6x = - 24 - 6 6x = - 30 x = - 5
Algebra4y-4 plus y plus 24 equals 6y plus 20-4YCombine like terms5y+20=2y+20Isolate Y3y=0y=0
- 8x + 8x = 0 so question is meaningless.
8x + 32 + 24 = 0 So 8x + 56 = 0 Subtract 56 from both sides: 8x = -56 Divide both sides by 8: x = -7
Yes because if 1+0=1 than 0 plus b equals b
The equation you are looking for is x + 5 = 0. To solve for x, you would subtract 5 from both sides of the equation. This would give you x = -5. Therefore, -5 plus 5 equals 0.
A=0 b=0 c=0
It can be simplified in the form of: 2x3+9x2-7x-34 = 0
No.
x = y = 0 ?