If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
-100(negative 100)+100(positive 100)=0. If you have 100 of something(the +100) and then take away 100 (the -100), you're left with nothing (the 0). So it's 0.
They touch each other at (0, 100) on the x and y axis.
x + 50 = 2x + 100 50 = 2x+100-x 50 = x + 100 50-100=x -50=x -50+50=0 -100+100=0 it is zero
Yes because if 1+0=1 than 0 plus b equals b
I would think -5 plus 5 equals 0.
A=0 b=0 c=0
100+0=100
It is B, 0.
x = y = 0 ?
many solutions
It equals 7