No.
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
They touch each other at (0, 100) on the x and y axis.
x + 50 = 2x + 100 50 = 2x+100-x 50 = x + 100 50-100=x -50=x -50+50=0 -100+100=0 it is zero
Yes because if 1+0=1 than 0 plus b equals b
A=0 b=0 c=0
100+0=100
It is B, 0.
many solutions
x = y = 0 ?
It equals 7
It equals 6
The graphs of the two equations will intersect when x² + 20x + 100 = y = x² - 20x + 100 Subtracting x² +100 from both sides you get 20x = -20x that will only be true when x = 0. At x = 0, y = 100 for both equations - so the point of contact would be (0,100)