To find this: You know (B+C) = 7. Therefore you know (A+A )= 21 - (B+C). Therefore 21-7 = 14. So now you know (A+A) = 14. So you divide (A+A)/2. This equals 7. Therefore A = 7.
c+c+c=6 C=2 Because: 2+2+2=6
7.5
a + c - b = 3 + 2 - 5 = 5 - 5 = 0
2 PbO + C -> 2 Pb + CO2
To find this: You know (B+C) = 7. Therefore you know (A+A )= 21 - (B+C). Therefore 21-7 = 14. So now you know (A+A) = 14. So you divide (A+A)/2. This equals 7. Therefore A = 7.
The answer is 21 because if 21 is divided by 3 it equals 7 plus 4 equals 11.
If: 3c = 6Then: c = 2
c+c+c=6 C=2 Because: 2+2+2=6
7.5
the answer is a
a + c - b = 3 + 2 - 5 = 5 - 5 = 0
2 PbO + C -> 2 Pb + CO2
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
144 Formula: c= (a2)+(ab)
b = sqrt32 or 4 root 2
If 2b a plus c, then we can say that 3tan A 2tan c = 21.