The balanced chemical equation for the given reaction is: PbO2 + PbO -> 2PbO + O2 Coefficients: 1 PbO2, 1 PbO, 2 PbO, 1 O2.
In this reaction, carbon (C) acts as a reducing agent. It reacts with lead oxide (PbO) to reduce it to elemental lead (Pb) while itself getting oxidized to carbon dioxide (CO2). This process is known as a redox reaction.
To balance the equation Pb(NO3)2 = PbO + NO2 + O2, start by balancing the elements that appear in only one compound on each side of the equation. In this case, balance the Pb first, followed by N and O. After balancing these elements, double-check to ensure that each element's count is the same on both sides of the equation. The brackets in the chemical formula indicate the composition of the ion or molecule enclosed within them.
When lead oxide reacts with carbon, the products are lead metal and carbon dioxide. The balanced chemical equation for this reaction is: PbO + C -> Pb + CO2.
The chemical reaction is:2 PbO + C = 2 Pb + CO2
2 PbO + C = 2 Pb + CO2
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The molar mass of lead(II) carbonate (PbCO3) is 267.2 g/mol. It decomposes into lead(II) oxide (PbO) with a molar mass of 223.2 g/mol. The equation is: PbCO3 → PbO + CO2. Using stoichiometry, we find that 2.50g of PbCO3 will produce 2.09g of PbO.
The chemical formula for lead(II) carbonate is PbCO3.
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The thermal decomposition of lead carbonate (PbCO3) produces lead oxide (PbO) and carbon dioxide (CO2) as the products.
Lead (II) oxide (PbO) reacts with water to form lead hydroxide (Pb(OH)2). The chemical equation for this reaction is: PbO + H2O -> Pb(OH)2. This reaction is an example of a metal oxide reacting with water to form a metal hydroxide.