Let pxy be a point on the parabola yx2 in the first quadrant consider the triangle pao formed by p a01 and the origin o00 and the triangle pbo formed by p b10 and the origin. Find perimeter area each?
perimeter of pao= the square root of (x^2+(x^2-1)^2) + square
root of (x^2 +x^4) and add 1 for the third side
Perimeter of PBO = the square root of ((x-1)^2+x^4) + square
root of (x^2+x^4) and again add 1 for third side