try this---> http://c-pgms.blogspot.com/2008/08/program-to-find-meanmedianand-mode_22.html
the median and mode are but the mean is not
The median is 9 and the mode is 18 and the mean is 11
Calculate the mean, median, and range with the outlier, and then again without the outlier. Then find the difference. Mode will be unaffected by an outlier.
mean: 1.7 median:1.7 mode: none
Mean, median, and mode are all equal in a normal distribution.
First of all rearrange the terms into Rank order. Hence 17,7,11,13,2,12,7 Becomes 2,7,7.11.12.13.17. The MEAN is the sum of all the terms divided by the number of terms. Hence [2+7+7+11+12+13+17] / 7 => [ 69 ]/7 = 9 6/7 = 9.85714.... ~ 9.86 ( 2 d.p). The MODE is the term that is most frequent, which is '7' The MEDIAN is the absolute middle term , which is '11'. The RANGE is the difference between the largest number and the smallest number, which is 17 - 2 = 15 !!!!!
Mean, median and mode are ways to find averages. The mode is the most common answer in a set of data. The median the number that is in the middle when the numbers are put in order. The mean is the statical average.
mode
No.
who discovered mean median and mode
the median and mode are but the mean is not
The median is 9 and the mode is 18 and the mean is 11
1,2,2,2,3
Calculate the mean, median, and range with the outlier, and then again without the outlier. Then find the difference. Mode will be unaffected by an outlier.
No. The mode will make some sense. The median and mode will not because there is not a linear scale in eye colour.
The mean is the average. The median is the middle. The mode is the most common.
The mean is 19. The median is 18. There is no mode.