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How to Calculate internal surface area swimming pool?
you maltiply the length by the wedth the proper way to calculate internal area lenght x the avg width. get three widths and aveg them than mutiply them time the lenght.
How do I calculate the number of gallons of water in our pool?
Multiply avg length times avg width times avg depth to get cubic feet them multiply by 7.48 to get gallons Question can't be answered without third deminsion. Formula: length times width times depth times 7.48 equals gallons
C program to calculate sum and average of 4 numbers?
/*mycfiles.wordpress.com To Calculate Sum & Average of 4 no.*/ #include<stdio.h> #include<conio.h> void main() { float a,b,c,d,sum,avg; clrscr(); printf("Enter the 4 nos.\n\n"); scanf("%f%f%f%f",&a,&b,&c,&d); sum=a+b+c+d; avg=(a+b+c+d)/4; printf("\nSum is= %f\nAverage is= %f",sum,avg); getch(); }
Write a program to calculate the average of n numbers using array?
C:#includeint main(){int num,sum,avg=0,i;printf("enter a number");scanf("%d",&num);for(i=0;i
What is the formula to calculate tons of silage in a pile?
It is avg. length X avg. width X avg. heigth = Cubic Feet. Well packed silage at the proper dry matter) should average about 45 lbs. as fed. (or 15 lbs of Dry matter at 66% moisture, 33% D.M. ) per Cubic foot. It can get a little tricky determining the averages because the way the pile may be sloped, etc. I.e....25' average width pile X 100' average length X Avg. height of 10' = 25,000 cubic feet. If this is packed well and at the proper moisture (66% moisture, 33% D.M.) there should be about 562 A.F. tons of silage in this pile, or about 188 tons of D.M. tons.
