20 + [(21+23)/22]2 = 20 + [44/22]2 = 20 + 22 = 20 + 4 = 24
Impossible, as there are not enough numbers to cover all squares.
One example. 12*8+3+7-6 = 100 The key is finding sets of 10s
If you must use all digits precisely once then the answer is: 8642, 8624, 8462
There are 210 of them, and I regret that I do not have the time to list them all.
To get 1000 using the numbers 1, 2, 3, and 4 only once in an equation, you can use the following mathematical expression: (4 x 2 x 3 x 1) x (4 + 2 + 3 + 1) = 1000. This equation involves multiplication and addition operations using all four numbers exactly once to achieve the desired result of 1000.
add them all together and then divide the answer by the number of numbers.
1
234, 243, 324, 342, 423, and 432.
Impossible, as there are not enough numbers to cover all squares.
One example. 12*8+3+7-6 = 100 The key is finding sets of 10s
You have 4 options for the first digit, 3 for the second, 2 for the third. Multiplying all this you get 4 x 3 x 2 = 24 options.
The four numbers that can be used in combinations or differences to make all numbers from 1 to 30 are 1, 2, 4, and 8. These numbers are powers of 2, which allows for the creation of all numbers from 1 to 30 through various combinations and differences. By using these four numbers strategically, one can generate any integer between 1 and 30.
All numbers can be expressed using exponents.
If you must use all digits precisely once then the answer is: 8642, 8624, 8462
There are 210 of them, and I regret that I do not have the time to list them all.
To get 1000 using the numbers 1, 2, 3, and 4 only once in an equation, you can use the following mathematical expression: (4 x 2 x 3 x 1) x (4 + 2 + 3 + 1) = 1000. This equation involves multiplication and addition operations using all four numbers exactly once to achieve the desired result of 1000.
9,876,543,210