20 + [(21+23)/22]2 = 20 + [44/22]2 = 20 + 22 = 20 + 4 = 24
Impossible, as there are not enough numbers to cover all squares.
One example. 12*8+3+7-6 = 100 The key is finding sets of 10s
If you must use all digits precisely once then the answer is: 8642, 8624, 8462
To get 1000 using the numbers 1, 2, 3, and 4 only once in an equation, you can use the following mathematical expression: (4 x 2 x 3 x 1) x (4 + 2 + 3 + 1) = 1000. This equation involves multiplication and addition operations using all four numbers exactly once to achieve the desired result of 1000.
There are 210 of them, and I regret that I do not have the time to list them all.
add them all together and then divide the answer by the number of numbers.
234, 243, 324, 342, 423, and 432.
1
Impossible, as there are not enough numbers to cover all squares.
One example. 12*8+3+7-6 = 100 The key is finding sets of 10s
You have 4 options for the first digit, 3 for the second, 2 for the third. Multiplying all this you get 4 x 3 x 2 = 24 options.
The four numbers that can be used in combinations or differences to make all numbers from 1 to 30 are 1, 2, 4, and 8. These numbers are powers of 2, which allows for the creation of all numbers from 1 to 30 through various combinations and differences. By using these four numbers strategically, one can generate any integer between 1 and 30.
If you must use all digits precisely once then the answer is: 8642, 8624, 8462
All numbers can be expressed using exponents.
There are 210 of them, and I regret that I do not have the time to list them all.
To get 1000 using the numbers 1, 2, 3, and 4 only once in an equation, you can use the following mathematical expression: (4 x 2 x 3 x 1) x (4 + 2 + 3 + 1) = 1000. This equation involves multiplication and addition operations using all four numbers exactly once to achieve the desired result of 1000.
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