You have 4 options for the first digit, 3 for the second, 2 for the third. Multiplying all this you get 4 x 3 x 2 = 24 options.
From left to right, pick the smallest possible digit every time. This will give you the smallest possible number.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
20From Rafaelrz,The number of three digit permutations you can get from the four different digits3. 6. 7. 9, is given by:4P3 = 4!/(4-3)! = 4x3x2x1/1 = 24
To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.
It is difficult to interpret exactly what you are trying to ask. If you allow your five digit number to have leading zeroes and do not allow negative numbers, then 00000 - 99999 = -99999 is the smallest number. If you do allow negative 5 digit numbers, then (-99999) - 99999 = -199998 is the smallest number.
3! = 6.
From left to right, pick the smallest possible digit every time. This will give you the smallest possible number.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
210
24680
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
There are 2 choices for every digit in the 6-digit number. So 26 is 2*2*2*2*2*2. The answer to that is 64.
625×2=1250
88,888
1,023.
123478
998,000