Yes because dividing all terms by 2 it becomes x2-6x-40 = (x-10)(x+4) when factored
2(x + 4)(x - 10)
If you mean: 2x2-11x+5 then it is (2x-1)(x-5) when factored
4x2+12x = 4x(x+3) when factored
Do you want its factorisation? 2x3 + 2x2 - 12x = 2x(x2 + x - 6) = 2x(x + 3)(x - 2).
Yes because dividing all terms by 2 it becomes x2-6x-40 = (x-10)(x+4) when factored
2x2 - 72 would be factored into (2x - 12)(x + 6) or (2x + 12)(x - 6) To double check, multiply each pair: (2x - 12)(x + 6) = 2x2 + 12x - 12x - 72 = 2x2 - 72 (2x + 12)(x - 6) = 2x2 - 12x + 12 x - 72 = 2x2 - 72
2(x + 4)(x - 10)
Operational signs would make this a lot easier. Assuming that's + 12x + 5, the answer is (2x + 1)(2x + 5)
If you mean: 2x2-11x+5 then it is (2x-1)(x-5) when factored
If that's 12x + 18, that can be factored to 6(2x + 3)
4x2+12x = 4x(x+3) when factored
Do you want its factorisation? 2x3 + 2x2 - 12x = 2x(x2 + x - 6) = 2x(x + 3)(x - 2).
whats the answer for -2x^3+2^2+12x
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
I assume your problem is: -2x3-2x2+12x-2x(x2-x-6)-2x(x-3)(x+2)
(-2x3 - 2x2 + 12x) = -2x (x2 + x - 6) = -2x (x + 3) (x - 2)