I assume your problem is: -2x3-2x2+12x-2x(x2-x-6)-2x(x-3)(x+2)
whats the answer for -2x^3+2^2+12x
it is below 555 and above 200 * * * * * x3 - 2x2 + 35x = x*(x2 - 2x - 35) = x*(x + 5)*(x - 7)
It is: 2x^2 -x -21
There are two forms in which a quadratic equation can be written: general form, which is ax2 + bx + c, and standard form, which is a(x - q)2 + p. In standard form, the vertex is (q, p). So to find the vertex, simply convert general form into standard form.The formula often used to convert between these two forms is:ax2 + bx + c = a(x + b/2a)2 + c - b2/4aSubstitute the variables:-2x2 + 12x - 13 = -2(x + 12/-4)2 -13 + 122/-8-2x2 + 12x - 13 = -2(x - 3)2 + 5Since the co-ordinates of the vertex are equal to (q, p), the vertex of the parabola defined by the equation y = -2x2 + 12x - 13 is located at point (3, 5)
-2x(x + 3)(x - 2)
I assume your problem is: -2x3-2x2+12x-2x(x2-x-6)-2x(x-3)(x+2)
-2x3 + 2x2 + 12x = -2x(x2 - x - 6) = -2x(x2 + 2x - 3x - 6) = -2x[ x(x + 2) - 3(x + 2) ] = -2x(x - 3)(x + 2)
2x2 + 15x + 25 = (2x + 5)(x + 5)
(2x+7)(x+7)
(-2x3 - 2x2 + 12x) = -2x (x2 + x - 6) = -2x (x + 3) (x - 2)
2x2+21x+49 = (2x+7)(x+7)
2x2 + 21x + 49 = 2x2 +14x +7x + 49 = 2x(x + 7) + 7(x + 7) = (2x + 7)(x + 7)
2x2+9x+9 = (2x+3)(x+3) when factored
whats the answer for -2x^3+2^2+12x
If you mean: 2x2+15x+25 then it is (2x+5)(x+5)
x(x + 5)(x - 7)