Yes, three rhombuses can form a hexagon. If each rhombus shares a side with another rhombus, they can be arranged in such a way that their combined shape outlines a hexagon. The internal angles of the rhombuses can align to create the necessary angles for a hexagon, allowing for a proper geometric configuration.
3 blue rhombuses cover one yellow hexagon.
3
The number of rhombuses that can fit in a hexagon depends on the size of the rhombuses relative to the hexagon. If we consider a regular hexagon and rhombuses that are formed by connecting the midpoints of the hexagon's sides, you can fit 6 rhombuses inside. However, if the rhombuses are of different sizes, the answer may vary.
3 if you don't make them overlap.
3 rhombuses will fit into one Hexagon...so it would be 20x3
Three rhombuses can be arranged to form a hexagon. A rhombus is a quadrilateral with all sides of equal length, so when three rhombuses are placed together, their sides can form a closed shape with six sides. The angles between the rhombuses will be 120 degrees, creating a regular hexagon.
3 rhombuses make a hexagon.
3 blue rhombuses cover one yellow hexagon.
3
The number of rhombuses that can fit in a hexagon depends on the size of the rhombuses relative to the hexagon. If we consider a regular hexagon and rhombuses that are formed by connecting the midpoints of the hexagon's sides, you can fit 6 rhombuses inside. However, if the rhombuses are of different sizes, the answer may vary.
3 if you don't make them overlap.
well that is easy its 3 rhombuses
3 rhombuses will fit into one Hexagon...so it would be 20x3
In general it cannot be done. In the rare case that the hexagon is regular, select three alternate vertices and draw lines to the centre (centroid) of the hexagon. These will form three congruent rhombi.
well that is easy its 3 rhombuses
3
To determine how many rhombuses can make four hexagons, we first need to understand the relationship between the shapes. A regular hexagon can be divided into six equilateral triangles, and if we consider a rhombus made of two triangles, it would take three rhombuses to create one hexagon. Therefore, for four hexagons, you would need 4 hexagons × 3 rhombuses/hexagon = 12 rhombuses in total.