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In general it cannot be done.

In the rare case that the hexagon is regular, select three alternate vertices and draw lines to the centre (centroid) of the hexagon. These will form three congruent rhombi.

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Q: How do you divide a hexagon to 3 congruent rhombuses?
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Related questions

How do you divide a hexagon into 3 parts to get 3 congruent quadrilaterals?

Assuming you have a regular hexagon, drawing a line between every other vertex and the center will give you three congruent quadrilaterals (that also happen to be parallelograms... in fact, they are rhombuses).


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3 rhombuses make a hexagon.


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What shape can 3 rhombuses make?

a hexagon


How many rhombuses make a hexagon?

3


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3


What three shapes make a hexagon?

well that is easy its 3 rhombuses


How many rhombuses are in one hexagon?

3 if you don't make them overlap.


How many rhombuses would fit into 20 hexagons?

3 rhombuses will fit into one Hexagon...so it would be 20x3


What three shapes make up a hexagon?

well that is easy its 3 rhombuses


How many congruent sides does a hexagon have?

Every hexagon has six sides. That's what the "hex" in hexagon means. Every polygon comes in two flavors and the hexagon can be either one of them ... 'regular' or 'irregular'. If the hexagon is a regular one, then all six of its sides are congruent. If the hexagon is an irregular one, then 2, 3, 4, 5, or none of its sides may be congruent.


How do you divide a hexagon into three equal parts?

This provided illustration (below) might not be terribly accurate but the three equal parts are meant to be the shapes of three rhombus'. All three lines join up in the center of the hexagon.______/ \ \/ \ \/ \____\ Hexagon divided into 3 equal rhombuses.\ / /\ / /\ /____/