64/4 = 16 with no remainder. The answer is yes, it does.
Yes, it goes in 16 times (16x4=64)
1, 2, 4.
No, 3 cannot go into 64 evenly. When you divide 64 by 3, the result is 21 with a remainder of 1. This means that 64 is not a multiple of 3.
1, 2, 4 and 8 will go into both numbers evenly with no remainders
No. 64 is not evenly divisible by six.
These whole numbers go evenly into 64: 1, 2, 4, 8, 16, 32, 64.
Yes, it goes in 16 times (16x4=64)
Not evenly because there will be a remainder of 4
1, 2, 4.
2, 4, and 8 will evenly divide into both.
Not evenly.
1, 2, 4 and 8 will go into both numbers evenly with no remainders
No. 64 is not evenly divisible by six.
1, 2, 4, 7, 8, 16, 32, 64, and of course 128 ;)
1, 2, 4, 8, 16, 32, 64, 128, 256.
No. These are the numbers that divide evenly into 64: 1 2 4 8 16 32 and 64.
It is just 1