Yes
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A/5 + 3 = 2Add Subtract 3 from both sides:A/5 = -1Multiply both sides by 5:A = -5
Yes. Because 135 is divisible by both 3 an 5, that is 135 can be divided by both 3 and 5 with no remainder.
3 x 5 x 41
5 x 123 = 615