15
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Yes
A/5 + 3 = 2Add Subtract 3 from both sides:A/5 = -1Multiply both sides by 5:A = -5
Yes. Because 135 is divisible by both 3 an 5, that is 135 can be divided by both 3 and 5 with no remainder.
-2x/3 - 5 = 5 Add 5 to both sides: -2x/3 = 10 Multiply both sides by 3: -2x = 30 Divide both sides by -2: x = -15
15, 30, 45, etc.