Yes.
You must solve the two simultaneous equations below:
x * y = 18
x - y = 10
When you do so, you will get two solution sets:
x = 11.557 (approx.)
y = 1.557 (approx.)
and
x = -1.557 (approx.)
y = -11.557 (approx.)
They are 10 and 1
The two numbers that have a difference of 2 and a product of 80 are 10 and 8. This is because 10 - 8 = 2 and 10 × 8 = 80. Thus, these numbers satisfy both conditions.
The two numbers that have a product of 56 and a difference of 10 are 14 and 4. This can be verified as 14 × 4 = 56 and 14 - 4 = 10.
10 and 3
14x4
26
They are 10 and 1
10 and 6 or 6 and 10
The two numbers that have a difference of 2 and a product of 80 are 10 and 8. This is because 10 - 8 = 2 and 10 × 8 = 80. Thus, these numbers satisfy both conditions.
The two numbers that have a product of 56 and a difference of 10 are 14 and 4. This can be verified as 14 × 4 = 56 and 14 - 4 = 10.
10 and 3
10 and 13 have a difference of 3 and a product of 130. 13 - 10 = 3 13 x 10 = 130
-5 * 5 = -25
12 x 2 = 24 12 - 2 = 10 The two numbers are therefore 2 and 12.
14x4
16*6=96. 16-6=10. 16 and 6.
54