The numbers are 10 and 8
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Let's denote the two square numbers as x^2 and y^2. The difference between two square numbers can be expressed as (x^2 - y^2), which can be factored into (x + y)(x - y). Since the difference is 80, we have (x + y)(x - y) = 80. The factors of 80 are 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80. By testing out different combinations of these factors, we find that the pair of square numbers that make a difference of 80 is 82^2 and 2^2.
A product is the result of multiplying two or more numbers. A single number cannot have a product.
There's only one number that's equal to 80. It's 80.There's a good chance that there could be three numbers whose sum is 80, or threedifferent numbers whose joint product is 80, but the question doesn't ask for those.
-10 + -8 = -18 -10 x -8 = 80 The two numbers are therefore -10 and -8.
8 + 10 = 188 x 10 = 80Therefore, the two numbers are 8 and ten